How many 1/6 pieces are in 6/12

Molly tried to evaluate 93\times5193×5193, times, 51 using partial products. Her work is shown below.

Mrac [35]

Since molly's solution tally's with the given solution, hence Molly's solution is correct.

Given the working on a partial product of 93 and 51 carried out by Molly as shown:

$\begin{array}{llrr} &&93 \\ &&\underline{{}\times51} \\ &\blueD{\text{Step 1}}&\blueD{3}& \blueD{1\times3\text{ ones}}\\ &\greenD{\text{Step 2}}&\greenD{90}& \greenD{1\times 9\text{ tens}}\\ &\maroonD{\text{Step 3}}&\maroonD{150}& \maroonD{50\times 3\text{ ones}}\\ &\goldE{\text{Step 4}}&\underline{{}+\goldE{ 4{,}500}}& \goldE{50\times 9\text{ tens}}\\ &\purpleD{\text{Step 5}}&\purpleD{4{,}743}& \end{array}$

This partial product can also be solved as shown below:

$93 \times 51 = (90+3)\times (50+1)$

Applying the distributive law:

$93 \times 51 = 90(50) + 90(1) + 3(50) + 3(1)\\93 \times 51 =4500 + 90 + 150 + 3\\93 \times 51 =4500+240+3\\93 \times 51 =4740+3\\93 \times 51 =4743$

Since molly's solution tally's with the given solution, hence Molly solution is correct.

Learn more about partial product at: brainly.com/question/24716925

5 0

2 years ago

Someone help me plzz

galina1969 [7]

Answer: y=5x+3
Step by step explanation:
Perpendicular meaning that the product of the slope/gradient is -1 hence ...
-1/5 * x = -1
x = -1/-1/5
x = 5
The equation perpendicular to y=-1/5x-3 is y=5x-c
Now it contains the points (1,2)
x variable is 1 and y variable is 2 plug them into the line equation
2=5(1)-c
2=5-c
2-5=-c
-3=-c divide by -1
3=c
Hence the perpendicular equation is y=5x+3
Hopefully it’s correct :)

5 0

2 years ago

In a box of 500 colored balls, 75 are black, 150 are green, 175 are red, 70 are white, and 30 are blue. what are the probabiliti

Oksanka [162]

If we want to select a ball of each colour we have to extract 175+150+75+70+1=471 balls

P=471/500 is the answer

4 0

3 years ago

Please help Algebra 1 Look at the photo below...

I am Lyosha [343]

horizontal line: x=9

vertical line: y=3

You can plug it into the application demos to see it visually just put y=3 on one line and x=9 on the other

7 0

3 years ago

The article "Occurrence and Distribution of Ammonium in Iowa Groundwater" (K. Schilling, Water Environment Research, 2002:177–18

Papessa [141]

Answer: 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

Step-by-step explanation:

Since we have given that

Number of alluvial wells = 349

Number of quaternary wells = 143

Number of alluvial wells that had concentrations above 0.1 = 182

Number of quaternary wells that had concentrations above 0.1 = 112

Average of alluvial wells = 0.27

Standard deviation = 0.4

Average of quaternary wells = 1.62

Standard deviation =1.70

So, 95% confidence interval gives

alpha = 5% level of significance.

$\dfrac{\alpha}{2}=2.5\%\\\\z_{\frac{\alpha}{2}}=1.96$

So, 95% confidence interval becomes,

$(1.62-0.27)\pm 1.96\sqrt{\dfrac{0.4^2}{349}+\dfrac{1.7^2}{143}}\\\\=1.35\pm 1.96\times 0.020\\\\=(1.35-0.040,1.35+0.040)\\\\=(1.31,1.39)$

Hence, 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

6 0

3 years ago