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ser-zykov [4K]
3 years ago
15

A school needs 175 light bulbs.Bulbs come in packages of 15.How many packages should the school order?

Mathematics
2 answers:
kkurt [141]3 years ago
6 0

Answer: 12 packages

Step-by-step explanation:

<em>Take 175 and divide it by 15</em>

<em>175/15</em>

<em>You will get 11.6</em>

<em>Since you are unable to order 11.6 packages you will need to order </em><em>12</em><em> packages to have enough lightbulbs.</em>

Svetllana [295]3 years ago
4 0

Answer:

the school would need to buy 12 pack and that will give them 180 light bulbs they will have 5 leftover

Step-by-step explanation:

15x11=165 thats not enough so they ened to buy 12 packs

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Ksivusya [100]

Answer:

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Step-by-step explanation:

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were going to have to get 3 on the other side, so were going to cancel it out and multipliy it because it is a fraction

now we would have 8v = 48*3

48*3=144

now the equation looks like this 8v = 144

to isolate v we can divide 8 on both sides

which brings us to v = 18

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Verdich [7]

Answer:

A) -18, 3, 24, 45, ...   f(1) = -18, f(n) = f(n-1) + 21 for n = 2,3,4,5,...

B) 11, 33, 55, 77, ...  f(1) = 11, f(n) = f(n-1) + 22 for n>1

C) -18, -108, -648, -3,888, ... f(1) = -18, f(n) = f(n-1) * 6 for n> 1

Step-by-step explanation:

-18, 3, 24, 45, ...

Let's take look at the possible difference patterns between terms:

-18 -> 3 ==> +21 or /-6

3 -> 24 ==> +21 or *8

We see we have a common pattern possible... +21

Which is confirmed from 24 to 45.

So the function will be f(1) = -18 of course

f(n) = f(n-1) + 21 for n = 2,3,4,5,...

11, 33, 55, 77, ...

Let's take a look at the possible difference patterns here again:

11 --> 33 ==> +22 or *3

33 --> 55 ==> + 22 or *5/3

Again, pattern of +22 confirmed with 55 -> 77

f(1) = 11

f(n) = f(n-1) + 22 for n>1

-18, -108, -648, -3,888, ...

Possible patterns:

-18 --> -108 ==> -90 or *6

-108 --> -648 ==> -540 or *6

Pattern of *6 confirmed with -648 and -3,888.

f(1) = -18

f(n) = f(n-1) * 6 for n > 1

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