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BARSIC [14]
3 years ago
14

HELP PLEASE IF YOU DO THANKS!

Mathematics
1 answer:
denpristay [2]3 years ago
4 0

Answer:

the pics are blocked

Step-by-step explanation:

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Help!?!? Find the area of the shaded region. Round your answer to the nearest hundredth.
Lerok [7]

Check the picture below.

so if y = 2, then 2y = 4, thus

\textit{area of a segment of a circle}\\\\A=\cfrac{r^2}{2}\left(\cfrac{\pi \theta }{180}~~ - ~~sin(\theta )  \right)~~\begin{cases}r=radius\\\theta =\stackrel{degrees}{angle}\\[-0.5em]\hrulefill\\r=4\\\theta =60\end{cases}\\\\\\A=\cfrac{4^2}{2}\left(\cfrac{\pi (60) }{180}~~ - ~~sin(60^o )  \right)\implies A=8\left( \cfrac{\pi }{3}~~ - ~~\cfrac{\sqrt{3}}{2} \right)\\\\\\A=\cfrac{8\pi }{3}~~ - ~~4\sqrt{3}\implies A\approx 1.45

7 0
2 years ago
A sample of 26 offshore oil workers took part in a simulated escape exercise, resulting in the accompanying data on time (sec) t
solniwko [45]

Answer:

The upper confidence bound for population mean escape time is: 379.27

The upper prediction bound for the escape time of a single additional worker  is 413.64

Step-by-step explanation:

Given that :

sample size n = 26

sample mean \bar x =  371.08

standard deviation \sigma = 24.45

The objective is to calculate an upper confidence bound for population mean escape time using a confidence level of 95%

We need to determine the standard error of these given data first;

So,

Standard Error S.E = \dfrac{\sigma }{\sqrt{n}}

Standard Error S.E = \dfrac{24.45 }{\sqrt{26}}

Standard Error S.E = \dfrac{24.45 }{4.898979486}

Standard Error S.E = 4.7950

However;

Degree of freedom df= n - 1

Degree of freedom df= 26 - 1

Degree of freedom df= 25

At confidence level of 95% and Degree of freedom df of  25 ;

t-value = 1.7080

Similarly;

The Margin of error = t-value × S.E

The Margin of error = 1.7080 × 4.7950

The Margin of error = 8.18986

The upper confidence bound for population mean escape time is = Sample Mean + Margin   of  Error

The upper confidence bound for population mean escape time is =  371.08 +  8.18986

The upper confidence bound for population mean escape time is = 379.26986  \approx 379.27

The upper confidence bound for population mean escape time is: 379.27

b.  Calculate an upper prediction bound for the escape time of a single additional worker using a prediction level of 95%.

The standard error of the mean = \sigma \times \sqrt{1+ \dfrac{1}{n}}

The standard error of the mean = 24.45 \times \sqrt{1+ \dfrac{1}{26}}

The standard error of the mean = 24.45 \times \sqrt{1+0.03846153846}

The standard error of the mean = 24.45 \times \sqrt{1.03846153846}

The standard error of the mean = 24.45 \times 1.019049331

The standard error of the mean = 24.91575614

Recall that : At confidence level of 95% and Degree of freedom df of  25 ;

t-value = 1.7080

∴

The Margin of error = t-value × S.E

The Margin of error = 1.7080 × 24.91575614

The Margin of error = 42.55611149

The upper prediction bound for the escape time of a single additional worker  is calculate by the addition of

Sample Mean + Margin of Error

= 371.08 + 42.55611149

= 413.6361115

\approx 413.64

The upper prediction bound for the escape time of a single additional worker  is 413.64

8 0
4 years ago
Find the value of x and y in the parallelogram below
avanturin [10]

Answer:

y = 41

x = 64

Step-by-step explanation:

8 0
3 years ago
Alexander signed up for a streaming music service that costs $9 per month. The service allows Alexander to listen to unlimited m
Viktor [21]

Answer:

$16.50

Step-by-step explanation:

The base price of the service is $9 and each song he downloaded is $0.50 so in turn you'd have to multiply 15(because he downloaded 15 songs) by $0.50 which would give you $7.50. then you'd add $9 and $7.50 to get $16.50

4 0
3 years ago
What is the volume of the triangular pyramid in the image? Round to the nearest tenth.
podryga [215]

Answer:

60 cm?

Step-by-step explanation:

4 0
3 years ago
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