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Alexus [3.1K]
3 years ago
9

Can someone explain this, please

Mathematics
1 answer:
xenn [34]3 years ago
3 0

Answer:

its the 3 one

Step-by-step explanation:

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Jumping makes a frog so tired, each successive jump is 2/3 the distance of the previous hump. If a frog jumps 24 cm on its first
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A restaurant has $3,600 to spend on Advertising if each at Cost $600 how many ads will the restaurant be able to purchase
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6

Step-by-step explanation:

If a restaurant has 3600 to spend on ads which costs 600 each, then they can buy 6 ads.

They can buy 6 ads since 3600/600 = 6.

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Each child has 4 apples. If there are 39 children, how many apples are there in total
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10
Alexeev081 [22]

Answer:

The expression you can use to find out how many boys is b + (b - 84) = 1824

There are 954 boys at Southside High School

There are 870 girls at Southside High School

Step-by-step explanation:

Assume that the number of boys in the Southside High School is b

∵ There are b boys in the Southside High School

∵ The number of girls is 84 fewer than boys

→ Subtract 84 from b to find the number of girls

∴ The number of girls in the Southside High School is (b - 84)

∵ Southside High School has a total of 1824 students

→ That means the sum of the numbers of the boys and the girls is 1824

∴ b + (b - 84) = 1824

∴ The expression you can use to find out how many boys is

   b + (b - 84) = 1824

→ Add the like terms in the left side

∴ (b + b) - 84 = 1824

∴ 2b - 84 = 1824

→ Add 84 to both sides

∵ 2b - 84 + 84 = 1824 + 84

∴ 2b = 1908

→ Divide both sides by 2 to find b

∵ \frac{2b}{2}=\frac{1908}{2}

∴ b = 954

∴ There are 954 boys at Southside High School

∵ The number of girls at Southside High School = b -84

→ Substitute b by 954

∴ The number of girls at Southside High School = 954 - 84

∴ The number of girls at Southside High School = 870

∴ There are 870 girls at Southside High School

4 0
3 years ago
HELP I NEED HELP ASAP
Roman55 [17]

9514 1404 393

Answer:

  C.  (10, 5), (5, 0), (0, 5)

Step-by-step explanation:

In order for the square to have an area of 50 square units, its side lengths must be √50 = 5√2 units long. The only way to get such a length with integer coordinates is for the sides of the square to be themselves the diagonals of a square 5 units on a side.

That is, two of the other vertices of the square must be among ...

  (5±5, 10±5) ⇒ (10, 15), (0, 15), (10, 5), (0, 5)

Only choice C contains two of the vertices on this list.

7 0
3 years ago
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