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ELEN [110]
3 years ago
8

Brittany and Natalie, start cycling together from their home to school, which is 14.4 miles away. Natalie takes 40 minutes to re

ach school and Brittany reaches 20 minutes after Natalie.
How much faster is Natalie (in mph)?
Mathematics
1 answer:
prohojiy [21]3 years ago
3 0

Answer:

7.2

Step-by-step explanation:

1. Natalie needed 40 minutes to get to school. In hours 40 minutes is 40/60= 2/3 hour (because there are 60 minutes in an hour). so her speed is 14.4/(2/3)= 14.4*3/2= 21.6 mph.

2. Britany needed 40+20= 60 min. 60 min= 1 hour. so she needed 1 hour her speed is 14,4/1= 14.4mph

3. The difference 21.6-14.4=7.2 is the answer .

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Find the measurements of the numbered angles in each isosceles trapezoid.
SSSSS [86.1K]

Answer:

∠1 = 96°

∠2 = 84°

∠3 = 84°

Step-by-step explanation:

∠1 = 96°

∠2 = ∠3

∠1 + 96 + ∠2 + ∠3 = 360°

∠2 = (360 - 96 - 96)/2 = 84°

∠3 = 84°

8 0
3 years ago
The tubs are similar in shape.
faltersainse [42]

Answer:

The tube are similar in shape.

The height of the small tub is 5  cm.

The volume of the small tube is 150  cm3.

The volume of the large tub is 500  cm3.

Work out the height of the large tub.

Give your answer correct to 3  significant figures.

Step-by-step explanation: Hope this help(:

3 0
9 months ago
Read 2 more answers
Gavin goes for a run at a constant pace of 9 minutes per mile. Ten minutes later, Lars goes for a run, along the same route, at
sweet [91]

Answer:  The answer is 35 minutes.


Step-by-step explanation:  Given that Gavin goes for a run at a constant pace of 9 minutes per mile and after 10 minutes, Lars started running along the same route, at a constant pace of 7 minutes per mile. We need to find the number of minutes Lars will take to reach Gavin.

In 9 minutes, distance run by Gavin = 1 mile.

So, in 1 minute, distance travelled by Gavin will be

d_G=\dfrac{1}{9}=\dfrac{7}{63}~\textup{miles}.

Similarly,

In 7 minutes, distance run by Lars = 1 mile.

So, in 1 minute, distance travelled by Lars will be

d_L=\dfrac{1}{7}=\dfrac{9}{63}~\textup{miles}.

Now, since Lars started after 10 minutes, so distance run by Gavin in those 10 minutes will be

d_{G10}=\dfrac{10}{9}=\dfrac{70}{63}~\textup{miles}.

Now, difference between Lars and Gavin's rate of runnings is

\dfrac{9}{63}-\dfrac{7}{63}=\dfrac{2}{63}.

Therefore, the time taken by Lars to reach Gavin is given by

t=\dfrac{\frac{70}{63}}{\frac{2}{63}}=35.

Thus, the required time is 365 minutes.  


6 0
3 years ago
triangle STU is an equilateral triangle. If ST is one less than twice x, SU is 37 less than five times x, and TU is 11 more than
maks197457 [2]

Answer:

The value of x = 12 and the measure of each side is 23 units.

Step-by-step explanation:

Given:  STU is an equilateral triangle.

ST = 2x -1

SU = 5x - 37

TU = x + 11

Now, as Δ STU is an equilateral triangle, hence all the sides of the triangle are equal.

⇒ ST = SU = TU

or, 2x -1 = 5x - 37 = x + 11

Considering : 2x -1 = 5x - 37 , we get

-1 + 37 = 5x - 2x

or 3x = 36

or, x = 12

Considering : 5x - 37 = x + 11 , we get

5x -x = 11 + 37

or, 4x = 48  or, x = 12

Considering :  x + 11  = 2x -1

or, 2x - 1 =  x + 11

or, x = 12

hence, in all the cases value of x = 12

ST =  2x -1 =  2(12) -1  = 23 units

SU =  5x - 37= 5(12) -1  = 23  units

TU =  x + 11  = 12 = 11  = 23 units

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3 years ago
Write a function rule for the table
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