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Elenna [48]
11 months ago
11

The tubs are similar in shape.

Mathematics
2 answers:
faltersainse [42]11 months ago
3 0

Answer:

The tube are similar in shape.

The height of the small tub is 5  cm.

The volume of the small tube is 150  cm3.

The volume of the large tub is 500  cm3.

Work out the height of the large tub.

Give your answer correct to 3  significant figures.

Step-by-step explanation: Hope this help(:

Arturiano [62]11 months ago
3 0
It will give you 3 types of figures
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A segment has an endpoint at (1,−2). The midpoint is at (−4,−2). What are the coordinates of the other endpoint?
vodka [1.7K]

Answer:

The other midpoint is located at coordinates (-9,-2) (Second option)

Step-by-step explanation:

<u>Midpoints</u>

If P(a,b) and Q(c,d) are points in \mathbb{R} ^2, the midpoint between them is the point exactly in the center of the line that joins P and Q. Its coordinates are given by

\displaystyle x_m=\frac{a+c}{2}

\displaystyle y_m=\frac{b+d}{2}

We are given one endpoint at P(1,-2) and the midpoint at M(-4,-2). The other endpoint must be at an equal distance from the midpoint as it is from P. We can see both given points have the same value of y=-2. This simplifies the calculations because we only need to deal with the x-coordinate.

The x-distance from P to M is 1-(-4)=5 units. This means the other endpoint must be 5 units to the left of M:

x (other endpoint)= - 4 - 5 = - 9

So the other midpoint is located at (-9,-2) (Second option)

5 0
3 years ago
Two collinear points on a line are given in the table below:
katrin [286]

Answer:

(4,3) and (7,2) do not lie on the line

Step-by-step explanation:

Given

(0,0)\ and\ (2,1)

Required

Determine which points that are not on the line

First, we need to determine the slope (m) of the line:

m = \frac{y_2 - y_1}{x_2- x_1}

Where

(x_1,y_1) = (0,0)

(x_2,y_2) = (2,1)

So;

m = \frac{y_2 - y_1}{x_2- x_1}

m = \frac{1 - 0}{2-0}

m = \frac{1}{2}

Next, we determine the line equation using:

y - y_1 = m(x -x_1)

Where

m = \frac{1}{2}

(x_1,y_1) = (0,0)

y - y_1 = m(x -x_1) becomes

y - 0 = \frac{1}{2}(x - 0)

y = \frac{1}{2}x

To determine which point is on the line, we simply plug in the  values of x to in the equation check.

For (4,2)

x = 4 and y =2

Substitute 4 for x and 2 for y in y = \frac{1}{2}x

2 = \frac{1}{2} * 4

2 = \frac{4}{2}

2=2

<em>This point is on the graph</em>

<em></em>

For (4,3)

x = 4 and y = 3

Substitute 4 for x and 3 for y in y = \frac{1}{2}x

3 = \frac{1}{2} * 4

3 = \frac{4}{2}

3 \neq 2

<em>This point is not on the graph</em>

<em></em>

For (7,2)

x = 7 and y = 2

Substitute 7 for x and 2 for y in y = \frac{1}{2}x

2 = \frac{1}{2} * 7

2 = \frac{7}{2}

2 \neq 3.5

<em></em>

<em>This point is not on the graph</em>

<em></em>

<em></em>(\frac{4}{8},\frac{2}{8})<em></em>

<em></em>x = \frac{4}{8} and<em> </em>y = \frac{2}{8}<em></em>

<em>Substitute </em>\frac{4}{8}<em> for x and </em>\frac{2}{8}<em> for y in </em>y = \frac{1}{2}x<em></em>

<em></em>\frac{2}{8} = \frac{1}{2} * \frac{4}{8}<em></em>

<em></em>\frac{2}{8} = \frac{1 * 4}{8 * 2}<em></em>

<em></em>\frac{2}{8} = \frac{4}{16}<em></em>

<em></em>\frac{1}{4} = \frac{1}{4}<em></em>

<em></em>

<em>This point is on the graph</em>

3 0
3 years ago
What is a polynomial​
luda_lava [24]

Answer:

In mathematics, a polynomial is an expression consisting of variables and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables. An example of a polynomial of a single indeterminate x is x² − 4x + 7

Step-by-step explanation:

6 0
3 years ago
615.44 rounded to the nearest tenth
Whitepunk [10]
The answer is 615.4

Hope this helps :)
5 0
3 years ago
Read 2 more answers
What is the slope of the line below? If necessary, enter your answer as a
Westkost [7]

9514 1404 393

Answer:

  6/5

Step-by-step explanation:

The slope formula is useful for finding the slope.

  m = (y2 -y1)/(x2 -x1)

  m = (-1 -11)/(-5 -5) = -12/-10

  m = 6/5

The slope of the line through the given points is 6/5.

3 0
3 years ago
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