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anzhelika [568]
3 years ago
8

HELP ME GUYS ITS URGENT!!!!!!

Mathematics
2 answers:
dalvyx [7]3 years ago
8 0

Answer:

option c.

angle 4 and angle 8.

vodka [1.7K]3 years ago
8 0

Answer:

i think its E i could be wrong

Step-by-step explanation:

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The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)
Lemur [1.5K]

Answer:

Cardiac output:F=0.055 L\s

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output:F=\frac{A}{\int\limits^T_0 {c(t)} \, dt} ---1

A = 3 mg

\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt

Do, integration by parts

[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}

[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}

[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}

Substitute the value in 1

Cardiac output:F=\frac{3}{54.49}

Cardiac output:F=0.055 L\s

Hence Cardiac output:F=0.055 L\s

4 0
3 years ago
4. What are the terms in the expression, 9- 4 + 3b + 7a?
Elan Coil [88]

Answer:

The terms are 9, 4, 3b and 7a.

The terms are 9 – 4 and 3b + 7a.

The terms are 9, -4, 3b, and 7a.

Step-by-step explanation:

7 0
3 years ago
How is 2:7 and 10000:35000 equivalent
Sati [7]

Answer:

Simplify both of them

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Here is a list of numbers:
ANEK [815]

Answer:

4.5

Hope it helps

5 0
2 years ago
One pipe can fill a pool in 9 hours. Another pipe can fill the pool in 6 hours. How long would it take them to fill the pool if
kow [346]

Answer:

3.6 hours or 3 hours and 36 minutes.

Step-by-step explanation:

If the first pipe can fill the pool in 9 hours that means that in 1 hour it fills \frac{1}{9} of the pool, we use the same logic for the second pipe and conclude that in 1 hour it feels up \frac{1}{6} of the pool. If both were to fill the pool together that means that in 1 hour they would fill...

\frac{1}{9} +\frac{1}{6} = \frac{5}{18} of the pool in 1 hour.

Now to find how many hours it will take divide the pool by the speed with which it is getting filled.

1 / \frac{5}{18} = 3.6 hours

3.6 hours in other words is 3 hours and 36 minutes.

3 0
3 years ago
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