Well, my math teacher told me to use the formula y=mx+b with +b being your y-intercept, mx being your constant or slope, and y= being your answer.EX: Sam is a babysitter who charges a fee of $15 and $5 per hour, how much would she get if she worked for 2 hours.+b would be 15 and m would be 5 and x is 2 and if you solve it would be $25.
How would Antonio respond....she would say " u stupid ".
Tess is right about it being easy to find 10% of 46 by moving the decimal point 1 place to the left to get 4.60.....but there is no need to do that twice....because if u do 10% twice, ur doing 20%.
okay....once u get 10% of 46 = 4.60....then u figure 5% of 46 = (0.05(46) = 2.30....because 10% + 5% = 15%.....then u add those together.....4.60 + 2.30 = 6.90. This can easily be checked...15% of 46 = 0.15(46) = 6.9 ,just like 10% of 46 + 5% of 46 = 6.9
Marilyn can cut 14 equal pieces
<em><u>Solution:</u></em>
Given that, Marilyn has 7/8 yard of ribbon
To find: Maximum number of 1/16 yard long pieces Marilyn can cut from this ribbon
From given information,
![\text{Total length of ribbon } = \frac{7}{8} \text{ yard }](https://tex.z-dn.net/?f=%5Ctext%7BTotal%20length%20of%20ribbon%20%7D%20%3D%20%5Cfrac%7B7%7D%7B8%7D%20%5Ctext%7B%20yard%20%7D)
![\text{Length of 1 piece } = \frac{1}{16} \text{ yard }](https://tex.z-dn.net/?f=%5Ctext%7BLength%20of%201%20piece%20%7D%20%3D%20%5Cfrac%7B1%7D%7B16%7D%20%5Ctext%7B%20yard%20%7D)
Number of pieces that can be cut from total length of ribbon is found by dividing the total length of ribbon by length of 1 piece
Therefore,
![\text{Number of pieces } = \frac{\text{Total length of ribbon}}{\text{Length of 1 piece }}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20pieces%20%7D%20%3D%20%5Cfrac%7B%5Ctext%7BTotal%20length%20of%20ribbon%7D%7D%7B%5Ctext%7BLength%20of%201%20piece%20%7D%7D)
Substituting the values, we get
![\text{Number of pieces } = \frac{\frac{7}{8}}{\frac{1}{16}}\\\\\text{Number of pieces } = \frac{7}{8} \times \frac{16}{1}\\\\\text{Number of pieces } = 14](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20pieces%20%7D%20%3D%20%5Cfrac%7B%5Cfrac%7B7%7D%7B8%7D%7D%7B%5Cfrac%7B1%7D%7B16%7D%7D%5C%5C%5C%5C%5Ctext%7BNumber%20of%20pieces%20%7D%20%3D%20%5Cfrac%7B7%7D%7B8%7D%20%5Ctimes%20%5Cfrac%7B16%7D%7B1%7D%5C%5C%5C%5C%5Ctext%7BNumber%20of%20pieces%20%7D%20%3D%2014)
Thus 14 pieces of ribbon can be cut
You can add and subtract suitable multiples of 2π to find your co-terminal angles.
5π/4 + 2π = 13π/4
5π/4 + 2·2π = 21π/4
5π/4 - 2π = -3π/4
5π/4 - 2·2π = -11π/4
Your angles can be {-11π/4, -3π/4, 13π/4, 21π/4}.
Answer:
Step-by-step explanation:
y(x) = (1/8)^x
y(1/3) = (1/8)^(1/3) = 0.5