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2 years ago

Quick I need to pass my test Bc 12:00

Mathematics

1 answer:

scoundrel [369]2 years ago

7 0

10. C) 160 feet

11. A) the first top left graph

please give me brainliest thank you

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Is triangle AXY inscribed in circle A? <br> yes no

Ratling [72]

Answer:

Δ AXY is not inscribed in circle with center A.

Step-by-step explanation:

Given: A circle with center A

To find: Is Δ AXY inscribed in circle or not

A figure 1 is inscribed in another figure 2 if all vertex of figure 1 is on the boundary of figure 2.

Here figure 1 is Δ AXY with vertices A , X and Y

And figure 2 is Circle.

Clearly from figure, Vertices A , X and Y are not on the arc/boundary of circle.

Therefore, Δ AXY is not inscribed in circle with center A.

8 0

3 years ago

Read 2 more answers

Which of the following describes a compound event? A) getting heads on a coin toss B) rolling an odd number on a die C) getting

jekas [21]

Combination event: 2 or more simple events/actions
The correct answer is D) because there are 2 actions in one description.

3 0

3 years ago

Read 2 more answers

HELPPPPP Find the missing parts of the triangle. Round to the nearest tenth when necessary or to the nearest minute as appropria

Romashka-Z-Leto [24]

The missing parts of the triangle ABC are A = 31.4°, B = 57.4°, C = 91.2°

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that a = 8.6 in, b = 13.9 in. and c = 16.5 in. Using cosine rule:

c² = a² + b² - 2abcosC

16.5² = 8.6² + 13.9² - 2(8.6)(13.9) * cosC

C = 91.2°

Also:

a² = b² + c² - 2bccosA

8.6² = 16.5² + 13.9² - 2(16.5)(13.9) * cosA

A = 31.4°

A + B + C = 180° (angles in a triangle)

31.4 + B + 91.2 = 180

B = 57.4°

The missing parts of the triangle ABC are A = 31.4°, B = 57.4°, C = 91.2°

Find out more on equation at: brainly.com/question/2972832

#SPJ1

3 0

2 years ago

Can i get help? Don’t really understand.

Rufina [12.5K]

First option: correct. This is because angles WOX and XOZ are supplementary, so

$m\angle WOX=180^\circ-104^\circ=76^\circ$

Second option: correct. By the inscribed angles theorem, we have

$m\angle XWZ=m\angle XYZ=\dfrac{113^\circ}2=56.5^\circ$

Angles WOX and YOZ are congruent because they form a vertical pair; they both have measure 76 degrees. This means angles WXY and WZY are also congruent, since the interior angles of any triangle sum to 180 degrees in measure. Therefore triangles WXO and YZO form a side-side-side pair, and all SSS triangles are similar.

Third option: not correct. There is a theorem (not sure what the name is) regarding intersecting chords that asserts the average of the measures of arcs WY and XZ is the same as the measure of angle XOZ. This means

$\dfrac{m\widehat{WY}+113^\circ}2=104^\circ\implies m\widehat{WY}=95^\circ$

Fourth option: not correct. This is because arcs WX and XZ are not "supplementary" in the sense that they do not form a semicircle and their measures do not add to 180 degrees. We know this because it's clear that point O is not the center of the circle. If it was, then angle XOZ would be a central angle and its measure would be the same as the arc XZ it subtends.

Fifth option: correct. The theorem mentioned in the assessment of the third option makes itself useful here. We have

$\dfrac{m\widehat{WX}+m\widehat{YZ}}2=m\angle WOX\implies m\widehat{WX}+m\widehat{YZ}=2\cdot76^\circ=152^\circ$

4 0

3 years ago

FIND THE AREA (LEAVE EXPLANATION)

KIM [24]

Answer:

Step-by-step explanation:

solve for two squares. Square 1: 32. Square 2: 8. answer: 32 + 8

3 0

3 years ago