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ladessa [460]
4 years ago
11

100 points!!! Multi-Step Equations with Distributive Property

Mathematics
2 answers:
ad-work [718]4 years ago
4 0

Answer:

An example below

Step-by-step explanation:

5(4a + 7(a + 2b))

First simply the inside bracket using distributive property:

7(a + 2b)

7(a) + 7(2b)

7a + 14b

5(4a + 7a + 14b)

5(11a + 14b)

Use distributive property again

5(11a) + 5(14b)

55a + 70b

Alexxandr [17]4 years ago
3 0

Answer:

x= -2

Step-by-step explanation:

An example could be

10 ( x+2) + 3(x+4) = 6(x+3)

Distribute

10x+20 +3x+12 = 6x+18

Combine like terms

13x +32 = 6x+18

Subtract 6x from each side

13x-6x +32 = 6x-6x+18

7x +32 = 18

Subtract 32 from each side

7x +32-32 = 18-32

7x =-14

Divide by 7

7x/7 = -14/7

x = -2

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Each 5 minutes is 30 degrees

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5 * pi/6 = 5 * 5 minutes = 25 minutes

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3 years ago
An experiment consists of first rolling a die and then tossing a coin: A. How many elements are there in the sample space? B. Le
stepladder [879]

Answer:

A) There are 12 elements in the sample space.

B) The required probability is 1/4 or 0.25.

C) Yes, the events are mutually exclusive.

Step-by-step explanation:

Consider the provided information.

Part(A)

An experiment consists of first rolling a die and then tossing a coin.

Thus the sample space is:

(1,H), (2,H) (3,H) (4,H) (5,H), (6,H)

(1,T), (2,T) (3,T) (4,T) (5,T), (6,T)

Hence, there are 12 elements in the sample space.

Part(B) Let A be the event that either a 2, 3 or 4 is rolled first, followed by landing a head on the coin toss.

Now consider the above sample space. There are 3 possible case in which 2, 3 or 4 is rolled first, followed by landing a head on the coin toss.

i.e (2,H) (3,H) (4,H)

The required probability is: P(A)=\frac{3}{12}=\frac{1}{4}=0.25

Hence, the required probability is 1/4 or 0.25.

Part(C)

Mutually exclusive, means that they cannot occur at the same time.

From part (B) Event A = (2,H) (3,H) (4,H)

Let B be the event that a number less than 2 is rolled, followed by landing a head on the coin toss.

Thus, the Event B = (1,H).

Therefore, Event A and B can't be occur at the same time as P(A and B)=0.

Hence, yes, the events are mutually exclusive.

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3 years ago
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Answer:

I suppose that the inequality is:

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To solve this we need to isolate c in one side of the inequality.

To isolate it, we need to multiply both sides by 11, then we get:

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c > 99.

To graph this, we will have an open dot at c = 99, and an arrow that points to the right direction.

The graph is shown below.

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Which set of data has the weakest linear association?
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