P L E A S E A N S W E R

Point E is on line segment DF. Given DE EF. 6 and DF =9, determine the length EF

nlexa [21]

Answer:

Step-by-step explanation:

IF point E lies on the line segment DF, this means that all the points DEF are collinear and DE+EF = DF.

Given parameter

DE = 6

DF = 9

Required

EF

Substituting the given parameter into the expression above to get the required will be;

DE+EF = DF.

EF = DF-DE

EF = 9-6

EF = 3

Hence the length of EF is equivalent to 3

5 0

3 years ago

The graph below shows the solution set of which inequality ?? HELP FASTTT

Maru [420]

Answer:

The graph shows the solution set of the equality √x < -1

(No Solutions)

4 0

3 years ago

Multiple choice questions will mark brainlist answer asap

Vesna [10]

11, -8, and 7 are the answers...

Please mark as brainliest... I really need it...

3 0

3 years ago

If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle

stira [4]

Answer:

The equation of the circle (x +1) )² +(y-(2))² = (2(√5))²

 or 

The equation of the circle x² + 2 x + y² - 4 y = 15

Step-by-step explanation:

Given points end Points are p(-3,-2) and q( 1,6)

The distance of two points formula

P Q = $\sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2} }$

P Q = $\sqrt{1 - (-3)^{2} + ((6 -(-2))^{2} }$

P Q = $\sqrt{16+64} = \sqrt{80}$

The diameter 'd' = 2 r

2 r = √80

= $\sqrt{16 X 5}$

= $4 \sqrt{5}$

r = 2√5

Mid-point of two end points

$(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )$

= (-1 ,2)

Mid-point of two end points = center of the circle

(h,k) = (-1 , 2)

The equation of the circle

(x -h )² +(y-k)² = r²

(x -(-1) )² +(y-(2))² = (2(√5))²

x² + 2 x + 1 + y² - 4 y + 4 = 20

x² + 2 x + y² - 4 y = 20 -5

x² + 2 x + y² - 4 y = 15

Final answer:-

The equation of the circle (x +1) )² +(y-(2))² = (2(√5))²

 or 

The equation of the circle x² + 2 x + y² - 4 y = 15

6 0

3 years ago

The martinez family has a walkway around their swimming pool. the area of the walkway can

DiKsa [7]

The width of the walkaway be 4 feet.

<h3>What is Discriminant Formula?</h3>

The discriminant formula is used to determine the nature of the roots of a quadratic equation. The discriminant of a quadratic equation $ax^{2} +bx+c=0$ is D = $b^{2} -4ac$

If D > 0, then the equation has two real distinct roots.

If D = 0, then the equation has only one real root.

Given that: $Area\; of \;walkway,\; a(w)\;= 4w^{2} + 100 w$

also, area of walkaway = 464 square feet.

So, $4w^{2} + 100 w =464$

$4w^{2} + 100 w -464=0$

Using Discriminant method,

a=4, b=100, c=-464

$w= \frac{-b\pm\sqrt{b^{2}-4ac} }{2a}$

w= $\frac{-100\pm\sqrt{(100)^{2}-4*4*(-464)} }{2*4}$

w= $\frac{-100\pm\sqrt{17424} }{8}$

So, $w_1= \frac{-100+\sqrt{17424} }{8} \;\;\;\; w_2= \frac{-100-\sqrt{17424} }{8}$

$w_1= \frac{-100+132 }{8} \;\;\;\; w_2= \frac{-100-132}{8}$

$w_1 = 4 \;\;\;\; and \;\;\; w_2= -29$

Hence the width of the walkaway be 4 feet.

Learn more about discriminant formula here:

brainly.com/question/2615966

#SPJ1

8 0

2 years ago