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2 years ago

9

P L E A S E A N S W E R

1 answer:

Pavlova-9 [17]2 years ago

5 0

Answer:

7-8

Step-by-step explanation:

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Two random variables x and y are independent if the value of x does not affect the value of y. If the variables are not indepen

jeyben [28]

Answer: $\mu_{x+y} =$ 3026

$\mu_{x-y}=$ 30

Step-by-step explanation: Average sum of the female and male's test score is the sum of expected value of each gender:

$\mu_{x+y}=\mu_{x}+\mu_{y}$

Assuming x represents the random male selected and y represents the random female selected:

$\mu_{x+y}=1528+1498$

$\mu_{x+y}=$ 3026

The average sum of their scores is 3026.

Average difference is the difference between the expected value (mean) of each gender:

$\mu_{x-y}=\mu_{x}-\mu_{y}$

$\mu_{x-y}=$ 1528 - 1498

$\mu_{x-y}=$ 30

The average difference of their scores is 30.

6 0

2 years ago

A sociologist recorded the estimated life expectancies of women born in Center City. Use the data from women born in 1970 and 20

Veronika [31]

$Y=0.213x-352$ will represent this linear model shown in the data table.

<h3>What will be the linear model for the given data?</h3>

Put the values of the x in the all given equations and then check the value of y if the value of y matches the given values in the option

So if we put the value x=1980 in the $Y=0.213x-352$ then

$Y=0.213(1980)-352$

$Y=69.74$

These values are closest to 70.1 whereas other options do not satisfy the condition.

Thus $Y=0.213x-352$ will represent this linear model shown in the data table.

To know more about Statistics follow

brainly.com/question/21508412

3 0

1 year ago

HELP PLEASE!!!! Which of these is a rational number?

MatroZZZ [7]

Answer:

es la B square root of 36/6

7 0

2 years ago

−8.5x + 0.36 = −3.04

erma4kov [3.2K]

X= 0.4

-8.5x=-3.4
x=0.4

4 0

2 years ago

Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Nastasia [14]

Answer:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

Step-by-step explanation:

Given

$9 < x < 10$ --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

$v = x^3$

For a uniform distribution, we have:

$x \to U(a,b)$

and

$f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.$

$9 < x < 10$ implies that:

$(a,b) = (9,10)$

So, we have:

$f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Solve

$f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Recall that:

$v = x^3$

Make x the subject

$x = v^\frac{1}{3}$

So, the cumulative density is:

$F(x) = P(x < v^\frac{1}{3})$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$ becomes

$f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.$

The CDF is:

$F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx$

Integrate

$F(x) = [v]\limits^{v^\frac{1}{3}}_9$

Expand

$F(x) = v^\frac{1}{3} - 9$

The density function of the volume F(v) is:

$F(v) = F'(x)$

Differentiate F(x) to give:

$F(x) = v^\frac{1}{3} - 9$

$F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}$

$F'(x) = \frac{1}{3}v^{-\frac{2}{3}}$

$F(v) = \frac{1}{3}v^{-\frac{2}{3}}$

So:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

8 0

2 years ago