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4 years ago

7

Need help!!! Due at 1:00!

1 answer:

LUCKY_DIMON [66]4 years ago

7 0

Answer: D

Step-by-step explanation:

multiply the denominators then the numerators

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$\begin{array}{c|l}\underline{\quad x\quad}&\underline{\quad 4^{-x}\qquad \qquad}\\-1&4^{-(-1)}=4^1=4\\\\0&4^{-(0)}=4^0=1\\\\2&4^{-(2)}=\dfrac{1}{4^2}=\dfrac{1}{16}\\\\4&4^{-(4)}=\dfrac{1}{4^4}=\dfrac{1}{64}\end{array}$

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