Write down some possibilities of the 2 numbers that add up to 32 first.
16+16, 15+17, 14+18, 13+19, 12+20
12 and 20 works because 12*5=60 and 20*3=60
Your answer is 12 and 20 (:
A. X is the number of years after 2000
2006-200 = 6 years.
Replace x with 6 and solve:
105(6)^2 + 680(6) + 4296 = 12,156
Answer for part a: 12,156
Answer for part B.
There was just over 12,000 in 6 years , to get to 21,500 would be a little over 9,000 more 9/12 = 0.75
6 years x .75 = 4.5 years
6 + 4.5 = 10.5 years round to 10 years for estimating purposes
Answer for part b: about 10 years
Idk. ima go with blue, but dont count on it
The answer is: [C]: " ⁷/₆ " .
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Note:
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(5/3) - (1/2) = ? ;
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The LCD (lowest common denominator) of "2 and 3" is "6" ;
So we need to rewrite EACH fraction in the problem as a fraction with "6" in the denominator ;
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(5/3) = (?/6) ? ; (6÷3=2) ; (5/3) = (5*2)/(3*2) = 10/6 ;
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(1/2) = (?/6) ? ; (6÷2=3) ; (1/2) = (1*3)/(2*3) = 3/6 ;
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Rewrite the problem: " (5/3) - (1/2) " ; as:
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10/6 - 3/6 ;
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10/6 - 3/6 = (10 - 3) / 6 = (7/6) = 1 ⅙ .
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The answer is: " ⁷/₆ " ; or, write as: " 1 ⅙ " ; which corresponds to:
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Answer choice: [C]: " ⁷/₆ " .
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Answer:
Step-by-step explanation:
