10 + 1/2*4*48 => 10 + 2*48 => 10 + 96 = 106.
Answer:
640 m
Step-by-step explanation:
We can consider 4 seconds to be 1 time unit. Then 8 more seconds is 2 more time units, for a total of 3 time units.
The distance is proportional to the square of the number of time units. After 1 time unit, the distance is 1² × 80 m. Then after 3 time units, the distance will be 3² × 80 m = 720 m.
In the additional 2 time units (8 seconds), the ball dropped an additional
... (720 -80) m = 640 m
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<em>Alternate solution</em>
You can write the equation for the proportionality and find the constant that goes into it. If we use seconds (not 4-second intervals) as the time unit, then we can say ...
... d = kt²
Filling in the information related to the first 4 seconds, we have ...
... 80 = k(4)²
... 80/16 = k = 5
Then the distance equation becomes ...
... d = 5t²
After 12 seconds (the first 4 plus the next 8), the distance will be ...
... d = 5×12² = 5×144 = 720 . . . meters
That is, the ball dropped an additional 720 -80 = 640 meters in the 12 -4 = 8 seconds after the first data point.
Answer:
Range A = 386ft
Range B = 427ft
B has the larger range.
Explanation:
To find the range, find the difference between the minimum and maximum depths for each submarine. Remember that your answer will be positive.
Sub A:
-146ft - (-532ft) = 386 ft
Sub B:
-194ft - (-621ft) = 427 ft
Submarine B has a larger range.
Answer:
Note that it is not a perfectly elastic result so it is <em>irrational</em><em> </em>
