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shusha [124]
2 years ago
7

Which equation is a function

Mathematics
1 answer:
suter [353]2 years ago
5 0
The answer is A!! Hope I helped
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Four resistors are connected in series such that their total resistance is 50ohm . If the resistance of resistors is 5 ohm , 10o
Katyanochek1 [597]
<h2>Answer:</h2>

\boxed{R_{4}=20\Omega}

<h2>Step-by-step explanation:</h2>

If resistors are in series, so the current  I is the same in all of them. In this problem we have four resistors. So, we can get a relationship between the Equivalent resistance  of series combination and the four resistors as follows:

R_{eq}=R_{1}+R_{2}+R_{3}+R_{4}

R_{eq} is the total resistance 50\Omega. Moreover:

R_{1}=5\Omega \\ R_{2}=10\Omega \\ R_{3}=15\Omega

Therefore:

50=5+10+15+R_{4} \\ \\ R_{4}=50-(5+10+15) \\ \\ R_{4}=50-30 \\ \\ \boxed{R_{4}=20\Omega}

7 0
3 years ago
EXPERTS/ACE/GENIUSES
BlackZzzverrR [31]
Answer is first one

(2,3)(4,2)(3,1)
3 0
3 years ago
Graph ARST with vertices R(6, 6), S(3, -6), and T(0, 3) and its image after a
padilas [110]

Answer:

The answer is the second figure and the vertices of Δ R'S'T' are:

R' = (-6 , 6) , S' = (-3 , -6) , T' = (0 , 3)

Step-by-step explanation:

* Lets revise some transformation

- If point (x , y) reflected across the x-axis

 ∴ Its image is (x , -y)

- If point (x , y) reflected across the y-axis

 ∴ Its image is (-x , y)

- If point (x , y) reflected across the line y = x

 ∴ Its image is (y , x)

- If point (x , y) reflected across the line y = -x

 ∴ Its image is (-y , -x)

- Now we can solve the problem

∵ R = (6 , 6) , S = (3 , -6) , T = (0 , 3), they are the vertices of ΔRST

- The triangle RST is reflected over the y-axis

- According to the rule above the signs of x-coordinates will change

∵ R = (6 , 6)

∴ Its image is (-6 , 6)

∵ S = (3 , -6)

∴ Its image is (-3 , -6)

∵ T = (0 , 3)

∴ Its image is (0 , 3)

* Now lets look to the figure to find the correct answers

- The image of Δ RST is ΔR'S'T'

∵ The vertices of the image of ΔRST are:

  R' = (-6 , 6) , S' = (-3 , -6) , T' = (0 , 3)

* The answer is the second figure

7 0
3 years ago
what is the solution to the equation fraction 3 over 5 n minus fraction 4 over 5 equals fraction 1 over 5 n? n = −1 n = 2 n = fr
Norma-Jean [14]
3/5n - 4/5 = 1/5n....multiply everything by 5 to get rid of the fractions
3n - 4 = n
-4 = n - 3n
-4 = -2n
-4/-2 = n
2 = n <==
4 0
3 years ago
Read 2 more answers
Rewrite the following equation in slope-intercept form.
ahrayia [7]
Pretty Sure it’s y=x+(-.8) haven’t done algebra in a bit. Sorry if wrong. :/
8 0
2 years ago
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