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3 years ago

Question 7 of 12 Solve: 3x- 8 = 6(1 - 2x) + 16 O A. x = 2 O B. x = 5 O C. x= -2 O D. There are infinitely many solutions.

Mathematics

1 answer:

Murljashka [212]3 years ago

6 0

Answer:

A. x =2

Step-by-step explanation: Rearrange terms 3x - 8 = 6 ( 1 - 2x ) + 16 ---> 3x - 8 = 6 ( -2x + 1 ) +16

Distribute

Add the numbers

Add 8 to both sides of the equation

Simplify

Add 12x to both sides of the equation

Simplify

Divide both sides of the equation by the same term

Simplify -------> x=2

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3 years ago

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3 years ago

Given the Venn Diagram what is the probability that a person is an only child OR only has sisters?

Svetradugi [14.3K]

Based on the venn diagram of siblings, the probability of being an only child or having only sisters is d. 0.50.

<h3>What is probability of being an only child or having a sister?</h3>

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= (Number of those only sister + Number of only children) / Total number of people in poll

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= (8 + 7) / (8 + 10 + 5 + 7)

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2 years ago

Of 375 randomly selected students, 30 said that they planned to work in a rural community. Find 95% confidence interval for the

Artemon [7]

Answer:

The 95% confidence interval for the true proportion of all medical students who plan to work in a rural community is (0.0525, 0.1075).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 375, \pi = \frac{30}{375} = 0.08$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.08 - 1.96\sqrt{\frac{0.08*0.92}{375}} = 0.0525$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.08 + 1.96\sqrt{\frac{0.08*0.92}{375}} = 0.1075$

The 95% confidence interval for the true proportion of all medical students who plan to work in a rural community is (0.0525, 0.1075).

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3 years ago