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3 years ago

I don't get this!!!!!Help please!!!!!!

Mathematics

1 answer:

Westkost [7]3 years ago

8 0

I want to say the first one, but i do not know for sure.

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What problem led to playgrounds becoming more common in America cities

son4ous [18]

This link might help you :)

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3 years ago

I need help no one helps me never

emmainna [20.7K]

Answer:

Step-by-step explanation:

they all equal the same thing

hope this helps :)

8 0

3 years ago

Suma a trei numere este 30. Primul numar este de doua ori mai mare decat triplul celui de-al treilea numar si de doua ori mai ma

Sloan [31]

a + b + c = 30 ;
a = 6c ;
a = 2b ;

Then, c = a / 6 and b = a / 2 ;
a / 6 + a / 2 + a = 30 ;
a / 6 + 3a / 6 + 6a / 6 = 180 / 6 ;
10a = 180 ;
a = 18 ;
b = 9 ;
c = 3.

Good luck !

4 0

3 years ago

Please please please tell the answer

OlgaM077 [116]

Answer:

a. 0

b. 4^1

c. 14

d. 8

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

3 0

3 years ago

Read 2 more answers