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FinnZ [79.3K]
2 years ago
14

Pls can someone pls help me Please show your work

Mathematics
1 answer:
Lana71 [14]2 years ago
7 0

Answer:

x = 8

I dunno what the question is in the first place, but I assume you are solving for x.

Step-by-step explanation:

The two given angles are equivalent because they are parallel and they have a line that intersects.

The line creates two angles on each side of each line, which is 120 or 60 because there are 180 degs on a straight line.

The obtuse side is 120, and the -8 + 16x is also on an obtuse angle, showing that they are equal.

120 = -8 + 16x

128 = 16x

8 = x

x = 8

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Read 2 more answers
Find the average value of the function f(t)=(t-2)^2 on [0,6]
pentagon [3]

Answer:

2

Step-by-step explanation:

The "average value of function f(x) on interval [a, b] is given by:

                      f(b) - f(a)

ave. value = ---------------

                         b - a

Here f(t)=(t-2)^2.

Thus, f(b) = (b - 2)^2.  For b = 6, we get:

          f(6) = 6^2 - 4(6) + 4, or f(6) = 36 - 24 + 4 = 16

For a = 0, we get:

           f(0) = (0 - 2)^2 = 4

Plugging these results into the ave. value function shown above, we get:

                      16 - 4

ave. value = ------------ = 12/6 = 2

                         6 - 0

The average value of the function f(t)=(t-2)^2 on [0,6] is 2.


4 0
3 years ago
Find the volume of the sphere shown to the right. Give an answer in terms of pi and rounded to the nearest cubic unit.
Vladimir [108]
The correct answers are:
Exact volume = V = \frac{32}{3} \pi in^3
Approximate volume = V = 33.51 in^3 

Explanation:

The volume of the sphere is: V = \frac{4}{3} \pi r^3

Since r = 2 in

Hence
V = \frac{4}{3} \pi (2)^3 \\ V =  \frac{32}{3} \pi in^3 (exact)
V = 33.51 in^3 (approximate)
5 0
3 years ago
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