These calculations are based on the drawing of the file enclosed.
There are three right triangles.
From the big right triangle:
a^2 + b^2 = 25^2
From the small right triangle on the left side:
(25-x)^2 + 10^2 = a^2
From the small right triangle on the right side
x^2 +10^2 = b^2
=> (25-x)^2 + 10^2 + x^2 + 10^2 = a^2 + b^2
=> (25-x)^2 + 10^2 + x^2 + 10^2 = 25^2
=> 25^2 - 50x + x^2 + 10^2 + 10^2 = 25^2
=> x^2 -50x + 100 =0
Use the quadratic formular to find the roots:
x = 2.1 and x = 47.9
Distance from back: 25 - 2.1 = 22.9 ft
Answer: 22.9 ft
Answer:
A and D
Step-by-step explanation:
Since tangent is opposite/adjacent,
Tan 40 in this case would be x/3.8 (i used x because we don't know what the value is)
So, you set it up as an algebra problem
Tan40 = x/3.8
Multiply both sides by 3.8
3.8tan40 = x, Option A
And then, angle E is 50 degrees
So tan 50 = 3.8/x
Multiply both sides by x
tan50x = 3.8
Divide both sides by tan50
x= 3.8/tan50
So, A and D are both correct
Answer:
I think -10 is the answer
Answer:
Winner got 3920
Loser got 1470
Step-by-step explanation:
8 + 3 = 11
5390 / 11 = 490
490 * 8 = 3920
490 * 3 = 1470
