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Butoxors [25]
3 years ago
14

Andrew and karleigh each run for 1 hour

Mathematics
1 answer:
Maurinko [17]3 years ago
6 0

Answer:

ok

Step-by-step explanation:

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Three phones in a shipment of eighteen are known to be broken. A randomly selected phone is removed from the shipment and tested
statuscvo [17]

Answer:

\frac{14}{17}

Step-by-step explanation:

Number of phones broken = 3

Number of phones not broken = 15

Total number of phone in the shipment = 18

Since a not broken phone has been randomly selected, the number of phones not broken reduces to 14. And the total number of phones would be 17.

Pr(of newly selected phone NOT broken) = \frac{number of not broken phones}{total number of phones}

                                           = \frac{14}{17}

Therefore, the probability of the selected phone not being broken is \frac{14}{17}.

5 0
3 years ago
You estimate that a baby pig weighs 20 pounds. The actual weight of the baby pig is 16 pounds. Find the percent error
nlexa [21]
Divide 16 by 20 to find the percent.

16/20 = 0.8 = 8%

To check, multiply 20 by 0.08

20 x 0.08 = 16

Brainliest answer please? 3 more away from Expert!
7 0
4 years ago
Is y^2=x+5 a linear function? Explain?
vazorg [7]
No it is not linear because it would make a curved line
6 0
4 years ago
Read 2 more answers
To find the product of (−2√20k)(5√8k3), first write using a single radical. Which expression is equivalent to the given product?
ad-work [718]

Answer:

Assuming the variable is included under the radical,

-40k²√(10)

Step-by-step explanation:

(-2\sqrt{20k})(5\sqrt{8k^3})

First we will simplify the first factor,

-2\sqrt{20k}

We will write 20 as a product of factors:

-2\sqrt{4*5k}

We know the square root of 2 is 2, so we pull a 2 out:

-2(2)\sqrt{5k}\\\\=-4\sqrt{5k}

Now we will simplify the second factor,

5\sqrt{8k^3}

We will rewrite 8 as a product of factors, as well as the variable:

5\sqrt{2*4*k^2*k}

The square root of 2 is 2, so we pull a 2 out.  Additionally, the square root of k² is k, so we pull that out:

5(2)(k)\sqrt{2k}\\\\=10k\sqrt{2k}

This gives us the product

(-4\sqrt{5k})(10k\sqrt{2k})

Multiplying the coefficients, we have

-4(10k)(\sqrt{5k})(\sqrt{2k})\\\\=-40k(\sqrt{5k})(\sqrt{2k})

Multiplying the two radicals, we have

-40k\sqrt{5k*2k}\\\\-40k\sqrt{10k^2}

The square root of k² is k, so we pull a k out, leaving

-40k(k)\sqrt{10}\\\\=-40k^2\sqrt{10}

8 0
4 years ago
Read 2 more answers
Find an equation of the line passing through the point ( 6 , − 4 ) (6,-4) and perpendicular to 9 x − 3 y = 9 9x-3y=9 . Write you
MrMuchimi

Answer:

y =-\frac{1}{3}-2

Step-by-step explanation:

We are given;

  • A point (6, -4)
  • An equation of a line, 9x - 3y = 9

We are required to determine the equation a line passing through a point (6, -4) and perpendicular to the given line;

  • To answer the question we need to get the gradient of the given line first.
  • We write the equation 9x - 3y = 9  in the form of y = mx + c, where m is the slope;
  • That is;

y = 3x -3

  • Thus, the slope of the line is 3

But; m₁ × m₂ = -1 (For perpendicular lines)

Therefore;

m₂ = -1 ÷ 3

    = -1/3

Therefore, the slope of the line in question is -1/3 and the line passes through (6, -4).

To get its equation, we get another point (x, y)

Then;

\frac{y+4}{x-6}=\frac{-1}{3}

Thus;

3(y+4) = -1(x-6)\\3y + 12 = -x+6

In the form of slope-intercept, the equation will be;

3y = -x - 6\\y =-\frac{1}{3}-2

Thus, the equation of the line is;

y =-\frac{1}{3}-2

7 0
4 years ago
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