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4 years ago

3+2+110+87+64+9876+30+100=

2 answers:

6 0

Ok how you answer this is called a Calculator.... but anyway
Start with the bigger numbers and work your way down

9876
+ 110
----------
  9986
+ 100
----------
10,086
+      87
----------
10,174
+      64
-----------
10,248
+      30
-----------
10,278
+        3
-----------
10,281
+        2
-----------
10,283

10,283 is your answer

Korvikt [17]4 years ago

4 0

10,272 so easy use calculator

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3 years ago

Evaluate the expression when g = 6 and h = 7 <br> h + 9g

Norma-Jean [14]

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3 years ago

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Nady [450]

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3 years ago

NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=−4.9t2+121t

Alenkasestr [34]

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by

$h(t)=-4.9t^2+121t+283$

The sea level is represented by h = 0, therefore, to find the corresponding time when h splashes into the ocean we have to solve for t the following equation:

$h(t)=0\implies-4.9t^2+121t+283=0$

Using the quadratic formula, the solution for our problem is

$\begin{gathered} t=\frac{-(121)\pm\sqrt{(121)^2-4(-4.9)(283)}}{2(-4.9)} \\ =\frac{121\pm142.083778...}{9.8} \\ =\frac{121+142.083778...}{9.8} \\ =26.8452834694... \end{gathered}$

The rocket splashes after 26.845 seconds.

The maximum of this function happens at the root of the derivative. Differentiating our function, we have

$h^{\prime}(t)=-9.8t+121$

The root is

$-9.8t+121=0\implies t=\frac{121}{9.8}=12.347$

Then, the maximum height is

$h(12.347)=1029.99$

1029.99 meters above sea level.

6 0

2 years ago