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Georgia [21]
3 years ago
10

One number was divided by 15, followed by this quotient being multiplied by 2. Next, the product was added to 9. The total sum w

as 7, so what was the first divisor?
Mathematics
1 answer:
aksik [14]3 years ago
7 0
I believe it is 15.

-15/15=-1
-1x2= -2
-2+9= 7
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When Arjun makes hot cocoa, he adds 20\text{ mL}20 mL20, start text, space, m, L, end text of chocolate syrup for every 333 ounc
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Answer:

Arjun's brother

Step-by-step explanation:

Given

Arjun = 20mL chocolate syrup to 3 ounce of hot water

Brother = 45mL chocolate syrup to 6 ounce of hot water

Required

Which is more chocolatey?

To get which is more chocolatey, we simply calculate the unit rate of chocolate per 1 ounce of hot water.

Unit\ Rate = \frac{Chocolate\ Syrup}{Hot\ Water}

For Arjun

Unit\ Rate = \frac{20}{3}

Unit\ Rate = 6.67mL/oz

For his brother

Unit\ Rate = \frac{45}{6}

Unit\ Rate = 7.5mL/oz

By comparison 7.5 > 6.67

Hence, Arjun brother's chocolate is more chocolatey.

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Find the values of x, y, and z.
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68 degrees

Step-by-step explanation:

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Choose the statistical question. * please help now
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What is the inverse of the function fx = 2x-10
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Determine the coordinates of the vertices of the triangle to compute the area of the triangle using the distance formula (round
Karo-lina-s [1.5K]

Answer:

1. D. 50\text{ units}^2

2. D. 45 units.

Step-by-step explanation:

We have been two graphs.

1. To find the area of our given triangle we will use distance formula.

\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Upon substituting coordinates of base line of our triangle we will get,

\text{Base length of triangle}=\sqrt{(15-5)^2+(5-15)^2}  

\text{Base length of triangle}=\sqrt{(10)^2+(-10)^2}  

\text{Base length of triangle}=\sqrt{100+100}  

\text{Base length of triangle}=\sqrt{200}  

\text{Base length of triangle}=10\sqrt{2}  

Now let us find the height of triangle similarly.

\text{Height of triangle}=\sqrt{(20-15)^2+(10-5)^2}  

\text{Height of triangle}=\sqrt{(5)^2+(5)^2}  

\text{Height of triangle}=\sqrt{25+25}  

\text{Height of triangle}=\sqrt{50}  

\text{Height of triangle}=5\sqrt{2}  

\text{Area of triangle}=\frac{\text{Base*Height}}{2}

\text{Area of triangle}=\frac{10\sqrt{2}*5\sqrt{2}}{2}

\text{Area of triangle}=\frac{50*2}{2}

\text{Area of triangle}=50

Therefore, area of our given triangle is 50 square units and option D is the correct choice.

2. Using distance formula we will find the length of large side of triangle as:

\text{Large side of rectangle}=\sqrt{(14-1)^2+(21-8)^2}

\text{Large side of rectangle}=\sqrt{(13)^2+(13)^2}

\text{Large side of rectangle}=\sqrt{169+169}

\text{Large side of rectangle}=\sqrt{338}

\text{Large side of rectangle}=13\sqrt{2}

\text{Small side of rectangle}=\sqrt{(4-1)^2+(5-8)^2}

\text{Small side of rectangle}=\sqrt{(3)^2+(-3)^2}

\text{Small side of rectangle}=\sqrt{9+9}

\text{Small side of rectangle}=\sqrt{18}

\text{Small side of rectangle}=3\sqrt{2}

\text{Perimeter of rectangle}=2(\text{Length + Width)}

\text{Perimeter of rectangle}=2(13\sqrt{2}+3\sqrt{2}}

\text{Perimeter of rectangle}=2(16\sqrt{2}}

\text{Perimeter of rectangle}=32\sqrt{2}

\text{Perimeter of rectangle}=45.2548339959390416\approx 45

Therefore, the perimeter of our given rectangle is 45 units and option D is the correct choice.

8 0
4 years ago
Read 2 more answers
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