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3 years ago

consider the function g(x) = 54(1/3)x. evaluate g(0). what point does this indicate on the graph if g?

1 answer:

7 0

If we’re following order of operations PEMDAS it would be g(0)=54(1/3)0
54x1/3=18
18x0=0 therefore the answer to the equation is 0

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PLZ ANSWER ILL GIVE BRAINILEST2 box plots. The number line goes from 26 to 36. For Pleasantville Middle School, the whiskers ran

Svetach [21]

Answer:

I believe the answer is- The mean and MAD can accurately describe the "typical" value in the symmetric data set.

Step-by-step explanation:

The other answers don't make sense because the mean and MAD are being used for symmetrical distributions and asymmetrical means uneven distributions.

6 0

3 years ago

Read 2 more answers

EFGH is a parallelogram. Find the measure of EG.

gayaneshka [121]

Answer: 64

Step-by-step explanation:

If EFGH is a parallelogram, its diagonals bisect each other meaning EJ and JG are congruent.

EJ = JG

4w + 4 = 2w + 18

Subtract 2w from both sides

2w + 4 = 18

Subtract 4 from both sides

2w = 14

Divide both sides by 2

w = 7

EG = EJ + JG

EG = 4w + 4 + 2w + 18

EG = 6w + 22

Now that we know what 'w' is, we can substitute it for 7

EG = 6 (7) + 22

EG = 42 + 22 = 64

The measure of EG is 64.

Hope that helped!

7 0

3 years ago

Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar

Brrunno [24]

The distance between the two points is $d=8.6m$

The polar coordinate of A is $\left(4.47,296.57\right)$

The polar coordinate of B is $\left(4.24,135\right)$

Explanation:

The two points are $A(2,-4)$ and $B(-3,3)$

The distance between two points is given by,

$d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6$

Thus, the distance between the two points is $d=8.6m$

The polar coordinates of A can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $A(2,-4)$ , we get,

Distance = $\sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43$

To make the angle positive, let us add 360,

$\theta=360-63.43=296.57$

The polar coordinate of A is $\left(4.47,296.57\right)$

Similarly, The polar coordinate of B can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $B(-3,3)$ , we get,

Distance = $\sqrt{(3)^{2}+(3)^{2}}=4.24$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45$

To make the angle positive, let us add 360,

$\theta=180-45=135^{\circ}$

The polar coordinate of B is $\left(4.24,135\right)$

5 0

3 years ago

Lin rode a bike 20 miles in 150 minutes. If she rode at a constant speed, how far did she ride in 15 minutes? How long did it ta

coldgirl [10]

Hey there! :)

Answer:

First part: 2 miles.

Second part: 45 minutes

Third part: 8 mph.

Step-by-step explanation:

We can divide this question into 3 parts.

Begin by solving for the distance traveled after 15 minutes by creating a ratio:

$\frac{20 mi}{150min} = \frac{x}{15 min}$

Cross multiply:

20 · 15 = 150 · x

300 = 150x

300/150 = 150x/150

x = 2 miles.

2nd part: How long it took her to ride 6 miles.

Set up another ratio similar to the one used before:

$\frac{20 mi}{150min} = \frac{6mi}{x min}$

Cross multiply:

20 · x = 6 · 150

20x = 900

20x/20 = 900/20

x = 45 minutes.

3rd part:

For this part, we will need to convert from minutes to hours.

$\frac{20 mi}{150 min}* \frac{60 min}{1 hr} = \frac{1200mi}{150hr} = 8 mi/h$

Therefore, her speed is 8 mph.

5 0

3 years ago

Please help. solve for x

malfutka [58]

Step-by-step explanation:

Given,

Base of the triangle

$2 \sqrt{6}$

Hypotenuse of the triangle = 5

Height of the triangle = x

Therefore, According to Pythagoras Theorem,

${base}^{2} + {height}^{2} = {hypotenuse}^{2}$

$= > {(2 \sqrt{6)} }^{2} + {x}^{2} = {5}^{2}$

$= > 24 + {x}^{2} = 25$

$= > {x}^{2} = 25 - 24$

$= > {x}^{2} = 1$

$= > x = \sqrt{1}$

$= > x = 1$

Hence, the required value of <u>x is 1.</u>

7 0

3 years ago