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Fantom [35]
3 years ago
10

What is..x+8y=-157x+8y=-9

Mathematics
2 answers:
Reil [10]3 years ago
7 0
Y =-15/8 -x
y=-9/8 -7x
Sauron [17]3 years ago
6 0
The correct answer is x=1 and y=-2

to solve for x and y, you can either substitute equations or add or subtract the equation.
for my explanation, I will subtract equations.

to start, you must look at the xs and ys to find similarities. since they both have 8y, we can easily subtract the equations to cancel the y for now and find x
x+8y=-15. x+8y=-15
-(7x+8y=-9. = -7x-8y=9

when you subtract the equations you get
-6x=-6
dividing each side by -6 to get the x by itself will give you
x=1
then, solve for y by substituting the 1 in the x stop of either equation
I will be substituting the x in the first equation
1+8y=-15
8y=-16
y=8
both equations should give you the same answer
to check, substitute the x and y in the other equation
7(1)+8(-2)=-9
7-16=-9
-9=-9
so x=1 and y=-2
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A square is shown below. Which expression can be used to find the area, in square units, of the shaded triangle in the square?
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Use the remainder Theorem to find the remainder for the given division. (16z^4-1)/(z+1)
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Remainder Theorem: when a polynomial <em>P(x) </em>is divided <em>by (x - a), </em>the remainder is <em>P(a).</em>

<em />

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7 0
1 year ago
Really need help..... number 14:)
Soloha48 [4]
Without the actually predicted values in comparison to the real values it is only possible to give a very likely answer based on their scale:
a) is 25 million off, which sounds bad but when compared to a few billion in population it's not even 1%
b)3 billion is more than half the world population as error: very unlikely
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4 0
3 years ago
Consider a deck with 2626 black and 2626 red cards. You draw one card at a time and you can choose either guess on whether it is
gregori [183]

The maximum earning is v(r,b)

Let v(r,b) be the expected value of the game for the player, assuming optimal play, if the remaining deck has r red cards and b black cards.

Then v(r,b) satisfies the recursion

and

The stopping rule is simple: Stop when v(r,b)=0.

To explain the recursion . . .

If r,b>0, and the player elects to play a card, then:

  • The revealed card is red with probability \frac{r}{r+b}, and in that case, the player gets a score of +1, and the new value is V(r-1,b)
  • The revealed card is black with probability \frac{b}{r+b}, and in that case, the player gets a score of −1, and the new value is V(r,b-1)

Thus, if r,b>0, electing to play a card yields the value f(r,b).

But the player always has the option to quit, hence, if r,b>0, we get v(r,b)=max(0,f(r,b)).

Implementing the recursion in Maple, the value of the game is

v(26,26)=41984711742427/15997372030584

v(26,26)  ≈2.624475549

and the optimal stopping strategy is as follows . . .

  • If 24≤b≤26, play while r≥b−5.
  • If 17≤b≤23, play while r≥b−4.
  • If 11≤b≤16, play while r≥b−3.
  • If 6≤b≤10, play while r≥b−2.
  • If 3≤b≤5, play while r≥b−1.
  • If 1≤b≤2, play while r≥b.
  • If b=0, play while r>0.  

So, The maximum earning is v(r,b)

Learn more about PROBABILITY here

brainly.com/question/24756209

#SPJ4

4 0
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