3 years ago

V(t)=27,500(0.90)t. Find the value after 11 years

Mathematics

1 answer:

Alika [10]3 years ago

4 0

Answer:

8,630

Step-by-step explanation:

$V(t) = 27,500(0.90)^t$

$V(11) = 27,500(0.90)^{11}$

$V(11) = 27,500(0.3138)$

$V(11) = 8,630$

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