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Rainbow [258]
2 years ago
15

The height of a parallelogram is 3 times the base the base measures 4.5 cm what is the area of the parallelogram

Mathematics
1 answer:
Amiraneli [1.4K]2 years ago
8 0

The answer is 13.5cm,hope this help!

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Please help! Brainliest answer! Thank you
Readme [11.4K]

Answer:

?

Step-by-step explanation:

wut?

7 0
3 years ago
What is the 3rd term of the linear sequence below?7,9,11,13,15,...​
rodikova [14]

Answer:

11

Step-by-step explanation:

8 0
2 years ago
ANSWER FOR A BUNCH OF POINTS !!EASY!!
Tasya [4]

The correct option is D for the placement of regular polygon and the rhombus.

<h3>What is defined as the regular polygon?</h3>
  • A polygon is a two-dimensional enclosed image created by connecting three or more straight lines.
  • A rhombus is a special parallelogram because it meets the definition of a parallelogram, which is a quadrilateral to two pairs of parallel sides.
  • A polygon is made up of three parts:
  1. Sides: A side is a line segment that connects two vertices.
  2. Vertices: A vertex is the point where two sides meet.
  3. Interior and exterior angles An interior angle is an angle formed by joining the sides of a polygon within its enclosed surface.

As, all the given figures comes under the regular polygon, all are placed in the left circle.

But the three diagram in white, orange and blue colour are regular polygon along with rhombus.

Thus, all three are placed in the intersection of the both circle of the vein diagram.

To know more about the regular polygon, here

brainly.com/question/1592456

#SPJ1

8 0
1 year ago
Are the triangles Similar? (yes or no). If yes, by what
kakasveta [241]

Answer:

The triangles are not similar

Step-by-step explanation:

we know that

If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

<em>Triangle X.Y.Z</em>

\angle X=61^o

\angle Z=90^o

\angle Y=90^o-61^o=29^o ---> angle X and angle Y are complementary angles

<em>Triangle H.G.J</em>

\angle H=90^o-34^o=56^o ---> angle H and angle J are complementary angles

\angle G=90^o

\angle J=34^o

so

X.Y.Z is a61^o-90^o-39^o triangle

H.G.J is a56^o-90^o-34^o triangle

The measure of its corresponding angles are not congruent

therefore

The triangles are not similar

8 0
3 years ago
Help I don’t know the answer
Amanda [17]
D I have no explanation
4 0
3 years ago
Read 2 more answers
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