The number of advance tickets sold is 25 and same day tickets sold is 30.
Data Given;
- Advance Ticket = $30
- Same-day Ticket = $25
- Total Ticket = $60
- Total Cost of Ticket = $1625
<h3>System of Equations</h3>
Let the number of advance ticket be represented by x
Let the number of same-day ticket be represented by y
From the system of equations above, we can easily pick any to start our calculation.
Using equation (i),
x + y = 60
x = 60 - y ...equation(iii)
Put equation (iii) into equation (ii)
Put the value of y into equation (i)
From the calculation above, the number of advance tickets sold is 25 and same-day tickets is 30.
Learn more on system of equations here;
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Answer:
i need the anwser to
Step-by-step explanation:
For this problem we must set up some fractions in an equality. First, we put number of people in the numerator and number of hours in the denominator. After this we can plug in 24 to the numerator of the first fraction and 4 to the denominator of the first fraction (24/4). We then set the two fractions equal to each other and put 18 in the numerator of the second fraction and the variable X and the denominator of the second fraction (18/x). Lastly we cross multiply and then divide leaving X alone. This will be our answer. Therefore the answer is 3 hours.
Answer: 15%
Step-by-step explanation:
% change = change/ actual value x 100
Change = 11 .50 - 10 = 1.5
Therefore % change = 1.5/10 x 100
= 15%
Answer:
x = 0, y = -2
Step-by-step explanation:
-3x - 4y = 8 (1)
-4x - 3y=6 (2)
Multiply (1) by -4 and (2) by -3, we have:
12x + 16y = - 32 (3)
12x + 9y= -18 (4)
Subtract (4) from (3), we have:
(12x + 16y) - (12x + 9y) = - 32 - (-18)
<=> 7y = - 14
=> y = - 2
Replace y with - 2 in (3), we have x = 0
