Answer:
Use a compass to draw two equal arcs ...
Step-by-step explanation:
The attached diagram shows the construction of an angle bisector. First you draw arc DE, then arcs from D and E with the same radius that cross at F.
So, the step on your list is, "use a compass to draw two equal arcs from the intersection points of a previous arc and the legs."
If
![xy + x = 12](https://tex.z-dn.net/?f=xy%20%2B%20x%20%3D%2012%20)
, then
![\dfrac{d}{dt}(xy+x)= \dfrac{d}{dt}(12)](https://tex.z-dn.net/?f=%20%5Cdfrac%7Bd%7D%7Bdt%7D%28xy%2Bx%29%3D%20%20%5Cdfrac%7Bd%7D%7Bdt%7D%2812%29)
.
Use the chain rule:
![y\dfrac{dx}{dt}+x \dfrac{dy}{dt}+ \dfrac{dx}{dt}=0](https://tex.z-dn.net/?f=%20%20y%5Cdfrac%7Bdx%7D%7Bdt%7D%2Bx%20%5Cdfrac%7Bdy%7D%7Bdt%7D%2B%20%5Cdfrac%7Bdx%7D%7Bdt%7D%3D0)
,
Since x=2, y=5, <span>dx/dt = -3, then
</span>
![5\cdot (-3)+2\cdot \dfrac{dy}{dt}+(-3)=0, \\ 2\cdot \dfrac{dy}{dt}=18, \\ \dfrac{dy}{dt}=9](https://tex.z-dn.net/?f=5%5Ccdot%20%28-3%29%2B2%5Ccdot%20%5Cdfrac%7Bdy%7D%7Bdt%7D%2B%28-3%29%3D0%2C%20%5C%5C%202%5Ccdot%20%5Cdfrac%7Bdy%7D%7Bdt%7D%3D18%2C%20%5C%5C%20%5Cdfrac%7Bdy%7D%7Bdt%7D%3D9)
.
Step-by-step explanation:
hypotenuse =
![\sqrt{a {}^{2} + b {}^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7Ba%20%7B%7D%5E%7B2%7D%20%2B%20b%20%7B%7D%5E%7B2%7D%20%20%7D%20)
199 and 201
..................
Answer is A.
x2 = 2, x1 = -14 , m = 3 and = 2
plug in
(3/(3+5)(2(-14))+(-14)