22^4c-82. Is the equation I think you are looking for.
Solution:
Let the volume (in litres) of acids used be:
x1=amount of 25% acid
x2=amount of 40% acid
x3=3*x2=amount of 60% acid
Answer:
5y+6x-40=0
Step-by-step explanation:
y-2=-6/5(x-5)
5y-10=-6(x-5)
5y-10=-6x+30
5y+6x-10-30=0
5y+6x-40=0
-12/4= -3
18/5= 3.6
-2.5= -2.5
1/5= .2
10= 10
Ordered) -12/4, -2.5, 1/5, -2.5, 10
The median is 1/5 since it's in the middle of all five numbers.
Hope I could help! :)
X = - 1/3 or an alternate form x = -0.3, x = -3 to the power of -1
