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2 years ago

Ill give Brainliest!!!!!

Mathematics

2 answers:

Rus_ich [418]2 years ago

8 0

Answer: The mass of solid a is 4800 grams

Step-by-step explanation:

Hi, to answer this question we have to apply proportions:

For solid b = 40.32 cm2 / 6912 grams

For solid a = 28 cm2 / x grams

Where x is the mass of solid a.

So:

40.32 / 6912 = 28 / x

x = 28 / (40.32 / 6912)

x = 4800 grams

The mass of a is 4800 grams

Feel free to ask for more if needed or if you did not understand something.

Sedbober [7]2 years ago

7 0

Answer:

Step-by-step explanation:

a= 4000 grams

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Serhud [2]

Answer:

You should probably change the language on your computer if thats what your asking

Step-by-step explanation:

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2 years ago

Read 2 more answers

Chips suppose a computer chip manufacturer rejects 2% of the chips produced because they fail presale testing.

Artyom0805 [142]

(a) P( fifth one is bad) = P( first 4 are OK) * P(5th is bad)

= (0.98)^4 * 0.02 = 0.0184 or 1.84%

(b) this will be (0.98)^10 = 81.70%

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2 years ago

I need helpppp!!! With this question

rjkz [21]

The answer is 108cm^2 because it gives you the entire height of the shape minus the height of the rectangle the divide it by two to find the height of the triangles the find the area of all the different shapes then add it together

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2 years ago

The frequency distributions of two data sets are shown in the dot plots below.

fredd [130]

Answer:

1st, 4th and 6th statements are true.

Step-by-step explanation:

We have been given two dot-plots and we are asked to select all the true statements about given dot plots.

Let us write all the data points of both dot plots.

Data set 1:

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 7.

Data set 2:

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4.

1. The mean of data set 1 is greater than the mean of data set 2.

Let us find mean of both data sets.

$\text{Mean of data set 1}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}$

$\text{Mean of data set 1}=\frac{45}{19}$

$\text{Mean of data set 1}=2.3684\approx 2.37$

$\text{Mean of data set 2}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}$

$\text{Mean of data set 2}=\frac{38}{18}$

$\text{Mean of data set 2}=2.11$

We can see that mean of data set 1 is greater than mean of data set 2, therefore, 1st statement is true.

2. The mean of data set 1 is equal to the mean of data set 2.

Since mean of data set 1 is greater than mean of data set 2, therefore, 2nd statement is false.

3. The median of data set 1 is greater than the median of data set 2.

Since data set 1 has 19 data points, so median of data set 1 will be value of 10th data set, that is 2.

Our data set 2 has 18 data points, so median of data set 2 will be the average of 9th and 10th data points.

$\text{Median of data set 2}=\frac{2+2}{2}$

$\text{Median of data set 2}=\frac{4}{2}=2$

Since median of data set 2 is also 2, therefore, 3rd statement is not true.

4. The median of data set 1 is equal to the median of data set 2.

Since both data set's median is 2, therefore, 4th statement is true.

5. The standard deviation of data set 1 is smaller than the standard deviation of data set 2.

Using online SD calculator we get SD of data set 1 is 1.422 and SD of data set 2 is 0.936. Since 1.422 is greater than 0.936, therefore, 5th statement is false.

6. The data sets have the same interquartile range.

$Q_1\text{ of data set 1}=1$