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cupoosta [38]
2 years ago
6

Ill give Brainliest!!!!!

Mathematics
2 answers:
Rus_ich [418]2 years ago
8 0

Answer: The mass of solid a is 4800 grams

Step-by-step explanation:

Hi, to answer this question we have to apply proportions:

For solid b = 40.32 cm2 / 6912 grams

For solid a = 28 cm2 / x grams

Where x is the mass of solid a.

So:  

40.32 / 6912 = 28 / x  

x = 28 / (40.32 / 6912)

x = 4800 grams

The mass of a is 4800 grams

Feel free to ask for more if needed or if you did not understand something.

Sedbober [7]2 years ago
7 0

Answer:

Step-by-step explanation:

a= 4000 grams

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Which of the following equations could be solved for a radius? Select all that apply.
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Answer:

A = π · (r²)

Step-by-step explanation:

A =π · r² is the area of a circle.

While π · r² · h can also give you the radius, it can only do so for the Volume V, not the Area A.

V=lwh doesn't really apply for a circular object, as it requires the length and width. For circular objects, both are equal to the diameter of the object, and 2² · r² · h does not equal the Volume.

V= π · r³ seems awfully like the volume of a sphere, but there's something missing. The true volume of a sphere is V=\frac{4}{3} · π · r³, not V= π · r³.

A=\frac{1}{2}*b*h only applies for triangles.

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You're pretty sure that your candidate for class president has about 55% of the votes in the entire school. but you're worried t
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Part A:

A component is one voter's vote. An outcome is a vote in favour of our candidate.
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Part B:

A trial is 100 votes. We can stimulate the trial by randomly picking 100 two-digits numbers from 00 - 99. Whoever gets the majority of the votes wins the trial.



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What is the value of x2 + 4 for x = 5?<br><br> The x2 is x squared.
lana66690 [7]
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7 0
3 years ago
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Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE​
eduard

Answer:

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

Step-by-step explanation:

Given the matrices

A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}

B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}

Calculating AB:

\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}

Multiply the rows of the first matrix by the columns of the second matrix

                                   =\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}

                                   =\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}

Hence,

\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}

Therefore,

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

5 0
2 years ago
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