3)
(x/3)+(2/5)
(5x/15)+(6/15)
(5x+6)/15
4)
(2/x)+(3/7)
(14/7x)+(3x/7x)
(3x+14)/(7x)
5)
(x/2)+(1/3)+(x/4)
(6x/12)+(4/12)+(3x/12)
(9x+4)/12
3) x² - 121 = 0
x² = 121
x' = +√121
x' = 11
_______________
x'' = - √121
x'' = -11
Solution ⇒ S{-11 ; 11 } or (x-11)(x+11)
4) 4x² + 144 = 0
4x² = -144
x² = -144 / 4
x² = -36
x = √-36
No solution ⇒ S = ∅
5) z²+10z+21 = 0
Δ = 10² - 4(1)(21)
Δ = 100 - 84
Δ = 16
x' = (-10+4) / 2 = -6/2 = -3
x'' = (-10-4) / 2 = -14/2 = -7
Solution ⇒ S{ -7 ; -3} or (x+3)(x+7)
Answer:
Whats wrong??
Step-by-step explanation:
Answer:
Only if there 10 students, which isnt likely
Step-by-step explanation:
Answer: y=1x+4
Step-by-step explanation: the b (y-intercept) is 4 and when you go up 1/1 (1) it crosses the lines
