Answer:
a) $520
b) $580
c) Interest amount is same each year
Step-by-step explanation:
Given - Georgie put $500 in her savings account, earning interest at a rate of 4% each year. She did not make any more deposits or withdrawals.
To find - a) How much money was in the account after one year?
b) How much money was in the account after 4 years?
c) Was the amount of money earned in interest the same or different each year?
Proof -
Here given that,
Principal amount = $500
rate of interest = 4% = 4/100 = 0.04
Now,
a)
Amount = P [ 1 + RT ]
= 500 [ 1 + 0.04(1)]
= 500 [ 1 + 0.04] = 520
⇒Amount = $520
b)
Amount = P [ 1 + RT ]
= 500 [ 1 + 0.04(4)]
= 500 [ 1 + 0.16] = 580
⇒Amount = $580
c)
In 2nd year,
Amount = P [ 1 + RT ]
= 500 [ 1 + 0.04(2)]
= 500 [ 1 + 0.08] = 540
⇒Amount = $540
Now,
Interest in 1st year = 520 - 500 = 20
Interest in 2nd year = 540 - 520 = 20
So,
The interest amount is same each year
Kylan is correct because 10•5=50 and if we apply this rule to the statement, 60•5=300.
Answer:
<u>6x^3 -2x^2-11x + 4</u>
Step-by-step explanation:
(3x - 4)(2x^2 + 2x - 1)
(3x - 4)(2x^2 + 2x - 1)
[(3x)(2x^2 + 2x - 1)] + [-4(2x^2 + 2x - 1)]
6x^3 + 6x^2 - 3x -8x^2 - 8x + 4
6x^3 + [6x^2-8x^2] [- 3x- 8x] + 4
<u>6x^3 -2x^2-11x + 4</u>
Answer:
D. 81
Step-by-step explanation:
I think the attached photo supports for your question to be answered
Here is my answer:
Number of days: 30
Mean of the data set = (68 + 70*2 +74*2 +76*4 +78 +80*5 + 82*3 +84*5 + 88 +88*3 + 92*3) /30 = 81
Answer:
(-3,2)
Step-by-step explanation:
To solve this, I will use substitution. First, isolate y in one of the equations;
-2x+y=8
-3x-y=7
-2x+y=8 is the same as y=2x+8, Now plug y into the other equation to solve for x;
-3x-(2x+8)=7 Solve for x
-5x-8=7
-5x=15
x=-3, Now plug in x in either equation to solve for y;
-2(-3)+y=8
6+y=8
y=2, The answer to this system is (-3,2)