Therefore, the range is : {-4,-2,2}.....I realize choice c has all the y values listed, however, if u have repeating y values, u only have to list it once.

Step-by-step explanation:

6 0

3 years ago

In its monthly report, the local animal shelter states that it currently has 24 dogs and 18 cats available for adoption. Eight o

andrezito [222]

Answer with Step-by-step explanation:

We are given that

Total dogs=24

Total cats=18

Total animals=24+18=42

Male dogs=8

Male cats=6

Total male animals=8+6=14

Total female animals=42-14=28

Female cats=18-6=12

Dogs female=24-8=16

a.We have to find the probability that the pet is male, given that it is cat.

It means we have to find P(Male/cat)

Conditional probability: $P(A/B)=\frac{P(A\cap B)}{P(B)}$

P(Cat)= $\frac{18}{42}$

$P(male cat)=\frac{6}{42}$

$P(Male/cat)=\frac{\frac{6}{42}}{\frac{18}{42}}$

P(male/cat)= $\frac{6}{18}=0.33$

b. $P(female cat)=\frac{12}{42}$

$P(female)=\frac{28}{42}$

$P(Cat/Female)=\frac{\frac{12}{42}}{\frac{28}{42}}=\frac{12}{28}=0.43$

c.P(Dog)= $\frac{24}{42}$

$P(dog female)=\frac{16}{42}$

$P(female/dog)=\frac{\frac{16}{42}}{\frac{24}{42}}$

$P(female/dog)=\frac{16}{24}=0.67$

5 0

3 years ago