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3 years ago

A carpet measures 7 meters 3 decimeters in length and 4 meters

Mathematics

1 answer:

TEA [102]3 years ago

3 0

Answer:

29.2 metres squared

Step-by-step explanation:

because 3 decimetre equal 1 metre, 7 metres and 3 decimetre equal 7.3 metres.

now we just use the area formula to solve.

Area = Length × Width = 7.3 × 4 = 29.2 metres squared

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What is 12- (-8) +7 in integers

Irina-Kira [14]

Answer:

12+8+7=27

Step-by-step explanation:

just normal addition

4 0

2 years ago

Expand & simplify<br><br> (3x-4)^2 - (x+1)(x-1)<br><br> Please anyone? I'm really bad at maths-

Mnenie [13.5K]

The answer would be 8x^2-24x+17

5 0

3 years ago

This one is a tough one. If you can explain it to me that’ll me great.

Crazy boy [7]

Answer:

C. 73 if I have read the given angle measurements correctly.

The angle measurements I see are:

$219^\circ$

$(x-50)^\circ$

$(x+45)^\circ$ .

Step-by-step explanation:

Those angles together form a full rotation. A full rotation is equal to 360 degrees.

So we have the following equation to solve:

$219+(x-50)+(x+45)=360$

Combine like terms:

$(x+x)+(219-50+45)=360$

Simplify:

$2x+(219-5)=360$

$2x+214=360$

Divide both sides be 2:

$x+107=180$

Subtract 107 on both sides:

$x=180-107$

$x=73$

5 0

3 years ago

Read 2 more answers

Y=–6x+2<br> –12x – 2y=–4<br> How many solutions does this linear system have?

DerKrebs [107]

The linear equation y = -6x + 2; -12x - 2y = -4 has no solution

<h3>Linear equation</h3>

y = -6x + 2

-12x - 2y = -4

Substitute y = -6x + 2 into (2)

-12x - 2y = -4

-12x - 2(-6x + 2) = -4

-12x + 12x -4 = -4

-12x + 12x = - 4 + 4

0 = 0

Solve for x

y = -6x + 2

y - 2 = -6x

x = (y - 2) / -6

Substitute into (2)

-12x - 2y = -4

-12(y- 2)/ 6 - 2y = -4

(-12y + 24) / 6 - 2y = -4

-2y + 4 - 2y = 4

0 = 0

Learn more about linear equation:

brainly.com/question/4074386

#SPJ1

3 0

2 years ago

The length and width of a rectangle are measured as 55 cm and 49 cm, respectively, with an error in measurement of at most 0.1 c

valentina_108 [34]

Answer:

The maximum error in the calculated area of the rectangle is $10.4 \:cm^2$

Step-by-step explanation:

The area of a rectangle with length $L$ and width $W$ is $A= L\cdot W$ so the differential of <em>A</em> is

$dA=\frac{\partial A}{\partial L} \Delta L+\frac{\partial A}{\partial W} \Delta W$

$\frac{\partial A}{\partial L} = W\\\frac{\partial A}{\partial W}=L$ so

$dA=W\Delta L+L \Delta W$

We know that each error is at most 0.1 cm, we have $|\Delta L|\leq 0.1$ , $|\Delta W|\leq 0.1$ . To find the maximum error in the calculated area of the rectangle we take $\Delta L = 0.1$ , $\Delta W = 0.1$ and $L=55$ , $W=49$ . This gives

$dA=49\cdot 0.1+55 \cdot 0.1$

$dA=10.4$

Thus the maximum error in the calculated area of the rectangle is $10.4 \:cm^2$

4 0

3 years ago