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Goshia [24]
2 years ago
15

Help me please, i really don't understand!!

Mathematics
2 answers:
Gelneren [198K]2 years ago
6 0

Answer:

it's ok no problem take care

Nat2105 [25]2 years ago
4 0

Answer:

x plus 4 divided by 5 minus 9

x + 4 / 5 - 9

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Help(T_T)<br> "Give 7.897 correct to 2 decimal places"
Lynna [10]

Answer:

7.89 till two decimal places.....

hope it helps

7 0
2 years ago
A road has a 10% grade, meaning increasing 1 unit of rise to every 10 units of run.
fenix001 [56]

The grade is the ratio of rise to run, i.e. the slope aka the tangent.

\tan \theta = \dfrac{1}{10}

\theta = \arctan 0.1 \approx 5.711^\circ

Answer: (a) 6 degrees

For part b, the road is the hypotenuse c of a right triangle whose tangent of the small angle is 1/10.    The height h or rise is the side opposite the small angle.

\sin\theta = \dfrac h c

h = c \sin \theta

We could just take the sine of the angle we got but let's get it from the tangent exactly.

\cos^2 \theta + \sin ^2 \theta = 1

Dividing by squared cosine

1 + \tan ^2 \theta = 1/\cos^2 \theta = 1/(1- \sin^2 \theta)

(1- \sin^2 \theta) = 1/(1 + \tan^2 \theta)

\sin^2 \theta = 1 - 1/(1 + \tan^2 \theta)

\sin^2 \theta = 1 - 1/(1 + (1/10)^2) = 1-1/(101/100) = 1/101

h = c \sin \theta = 2 \sqrt{1/101} \approx 0.199

Answer: (b) Rise of 0.199 km

6 0
3 years ago
Which one of these are convexs
garik1379 [7]
B is the answer it is the only othe shplape
4 0
3 years ago
Is the relation a function?
son4ous [18]

Answer:

No

Steps- two rang values exist for domain value -2

8 0
3 years ago
Simplify the trigonometric expression.
Natasha_Volkova [10]
First we are going to find the common denominator of both fractions. To do that, we are going to multiply their denominators:
(1+sin \alpha )(1-sin \alpha )=1-sin^2 \alpha

Now we can rewrite our expression using the common denominator:
\frac{1-sin \alpha }{1-sin^2 \alpha } + \frac{1+sin \alpha }{1-sin^2 \alpha} = \frac{2}{1-sin^2 \alpha}

Finally, we can use the trig identities: 1-sin^2 \alpha =cos^2 \alpha and sec \alpha = \frac{1}{cos \alpha } to simplify our trig expression:
\frac{2}{cos^2\alpha}=2sec^2 \alpha

We can conclude that the correct answer is the fourth one.
5 0
3 years ago
Read 2 more answers
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