Martin and his 3 friends ate dinner at

What is the perimeter of the figure

Natalija [7]

Answer:

The perimeter of the figure is 111.46 units

Step-by-step explanation:

Given:

RS = 43

LS = 18√2

A right Triangle is attached to a Rectangle.

A right Triangle is having measure angle 45° , 90°

and Hypotenuse = 18√2

∴ The Third Angle measure will also be 45° {angles Sum property of a triangle}

∴ the right angled triangle is an Isosceles triangle.

∴ Two sides are equal LT = TS

To Find:

Perimeter of figure = ?

Solution:

we have

$\sin 45 = \frac{\textrm{side opposite to angle 45}}{Hypotenuse}\\$

we Know sin 45 = 1/√2

∴ $\frac{1}{\sqrt{2} }= \frac{LT}{18\sqrt{2}}\\\\\therefore LT = 18\ unit\\\\\therefore TS = 18\ unit\\$

Now ,

ARTL is a Rectangle

∴ opposite side of a rectangle are equal

∴ LT = AR = 18 unit

and AL = RT

But,

RT = RS - TS

= 43 - 18

25

∴ AL = RT = 25

∴ Perimeter of figure = AL + LS + RS + AR

= 25 + 18√2 + 43 + 18

= 86 + 18√2

= 111.455

= 111.46 units

∴ Perimeter of figure = 111.46 units

7 0

3 years ago

PLEASE HELP WILL MARK BRAINLIEST

Finger [1]

Answer:

figure ll only

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Which angles are remote interior angles?

AlladinOne [14]

Answer:

B: 2 and 3

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Suppose you are given a square with an inscribed circle as shown below. if the area of the square is 144 m2 what is the area of

Mashcka [7]

The area of the circle should be 113.097m^2

3 0

4 years ago

2. Solve the equation by completing the square. Show your work.

scoundrel [369]

Answer:

x = 5 or 25

Step-by-step explanation:

I think the method I am about to explain is slightly quicker and easier than the method in your question. This works for any 'complete the square' question.

We begin with x² - 30x = - 125.

First, we are going to factorise the left-hand side of the equation by dividing the 'b' value (-30) by 2 (you'll see why this works in a minute):

(x - 15)²

We want these brackets to multiply out to give x² - 30x, so that they equal the left-hand side of the equation. Unfortunately, if we multiply them out, we get:

(x - 15)(x - 15) =

x² - 30x + 225

There is an unwanted term (the + 225, from 15²)! We only want x² - 30x, so we have to remove this term by subtracting it from the left side of the equation. To do this, let's set up the original equation again:

(x² - 30x + 225) - 225 = - 125

Note: The reason why we don't have to subtract it from both sides is because the original equation is x² - 30x = - 125, and so we must make sure the left hand side is still equal to x² - 30x.

So now we know that (x - 15)² multiplies out to give x² - 30x +225, we can write this as (x - 15)² in our equation:

(x² - 30x + 225) - 225 = - 125

is the same as:

(x - 15)² - 225 = - 125

Now add 225 to both sides of the equation:

(x - 15)² = - 125 + 225 = 100

(x -15)² = 100

The next step is to square root both sides. Be careful here, and remember that √100 can either be 10 or -10, as (-10)² = 100. To indicate both results, write ±10 ("plus or minus 10").

√(x - 15)² = √100

x - 15 = ±10

Because, there are two possible values for the right-hand side of the equation, we need to separate our equation into two equations:

1. x - 15 = 10

and

2. x - 15 = -10

Now we solve these two simple linear equations for x:

1. x = 10 + 15 <- add 15 to both sides

x = 25 This is our first solution.

2. x = -10 + 15 <- add 15 to both sides again

x = 5 This is our other solution.

So our two solutions are x = 5 and x = 25!

I have attached the quick version of the working out for this question - that is what you would be expected to write down in a test.

5 0

4 years ago