Answer: Option C.
Step-by-step explanation:
The coordinates (x,y) of a terminal point for an angle θ are:
x = cos(θ) and y = sin(θ).
In this case, we have θ = 330°.
Then we have:
x = cos(330°) = 0.866 = (√3)/2
y = sin(330°) = -0.5 = -1/2
then the coordinates of the terminal point are ((√3)/2, -1/2)
Then the correct option is c.
Answer:
3
Step-by-step explanation:
2 + 2 = 4
4 - 1 = 3
The possible digits are:
5, 6, 7, 8 and
9. Let's mark the case when the locker code begins with a prime number as
A and the case when <span>the locker code is an odd number as
B. We have
5 different digits in total,
2 of which are prime (
5 and
7).
First propability:
</span>

<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with
5, 7 or
9 (three of five digits).
Second probability:
</span>
Answer:
Step-by-step explanation:
where f(x) is replaced by y
Take Laplace on both sides

We can resolve into partial fraction to get Y = L(y)
Let this equals

Solving we get
s=-9
24C = 10 or C =5/12
s=-2: A=10/12=5/6
s=-4: B = -5/4
Taking inverse Laplace

Agreed, I had to take a test on it and y did equal 70