36/54 and 6/9
is a pair of proportional fraction
Notice the picture
we have, the opposite side
the angle
and we want the hypotenuse
so recall your SOH CAH TOA
which one has all that? low and behold, is Ms Sine,
so let's bother Ms Sine
make sure your calculator is in Degree mode, since the angle here is in degrees, as opposed to Radian mode
The <em>total</em> area of all six faces of the tunnel is 
square centimeters.
<h2>Procedure - Surface area of a tunnel for a toy train</h2>
The surface area of the solid (
) used to represent the tunnel for a toy train is the sum of its six faces (two <em>semicircular</em> sections, inner <em>semicircular</em> arc section, outer <em>semicircular</em> arc section, two rectangles).
<h3>Determination of the surface area of the tunnel based on information of the diagram</h3>
We calculate the surface area as following:
![A = 2\cdot \frac{\pi}{2} \cdot [(10\,cm)^{2}-(8\,cm)^{2}] + \pi\cdot (8\,cm)\cdot (30\,cm) + \pi\cdot (10\,cm)\cdot (30\,cm) + 2\cdot (2\,cm)\cdot (30\,cm)](https://tex.z-dn.net/?f=A%20%3D%202%5Ccdot%20%5Cfrac%7B%5Cpi%7D%7B2%7D%20%5Ccdot%20%5B%2810%5C%2Ccm%29%5E%7B2%7D-%288%5C%2Ccm%29%5E%7B2%7D%5D%20%2B%20%5Cpi%5Ccdot%20%288%5C%2Ccm%29%5Ccdot%20%2830%5C%2Ccm%29%20%2B%20%5Cpi%5Ccdot%20%2810%5C%2Ccm%29%5Ccdot%20%2830%5C%2Ccm%29%20%2B%202%5Ccdot%20%282%5C%2Ccm%29%5Ccdot%20%2830%5C%2Ccm%29)
The <em>total</em> area of all six faces of the tunnel is square centimeters. 
To learn more on surface areas, we kindly invite to check this verified question: brainly.com/question/2835293
9514 1404 393
Answer:
(x, y) = (1/2, 5)
Step-by-step explanation:
We observe that the y-terms have coefficients 7 and -14. If we want to eliminate the y-terms, we need to multiply 7 by a factor that makes it be the opposite of -14. That factor will be -(-14)/7 = 2.
After multiplying the first equation by 2, we have ...
- 16x +14y = 78
- 4x -14y = -68
Adding these two equations gives ...
20x = 10
Solving for x, we need to divide by 20:
x = 10/20 = 1/2
Substituting this into the first equation, we get ...
8(1/2) +7y = 39
7y = 35 . . . . . . subtract 4
y = 35/7 = 5 . . . divide by 7
Then the solution is (x, y) = (1/2, 5).
_____
<em>Check</em>
We used the first equation to find y, so we know the x- and y-values satisfy the first equation. We need to check the result using the second equation.
4(1/2) -14(5) = -68
2 -70 = -68 . . . . . . . true; result checks OK
Answer:
sin Ф = 3/√13; cos Ф = 2/√13; and tan Ф = 3/2
Step-by-step explanation:
Let's assume we're limiting ourselves to Quadrant I.
Start with the tangent function. tan Ф = opp / adj.
In this case opp = 3 and adj = 2.
The length of the hypotenuse is found using the Pythagorean Theorem and is √(3² + 2²) = √13.
Then sin Ф = opp / hyp = 3/√13 or 3√13/13
and
cos Ф = adj / hyp = 2/√13 or 2√13/13
and (as before)
tan Ф = opp / adj = 3/2
