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Liono4ka [1.6K]
2 years ago
15

LOST HOPE PLEASE HELP

Mathematics
1 answer:
Kisachek [45]2 years ago
7 0
750 inches.
(base*height)/2
(25*60)/2
1500/2
answer=750
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The area of a rectangle is 229.2 m2. If the length is 15 m, what is the perimeter of the rectangle
igor_vitrenko [27]

Answer:

\large\boxed{P=60.56\ m}

Step-by-step explanation:

The formula of an area of a rectangle:

A=lw

l - length

w - width

We have

A=229.2\ m^2\\\l=15\ m

Substitute:

15w=229.2          <em>divide both sides by 15</em>

w=15.28\ m

The formula of a perimeter of a rectangle:

P=2(l+w)

Substitute:

P=2(15+15.28)=2(30.28)=60.56\ m

8 0
3 years ago
Ron has 2,500 pounds of horse feed to deliver. He wants to deliver an equal amount on each of 4 trips.
uysha [10]
4f=2500 because 4 trips from 2500 means f= \frac{2500}{4}.
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3 years ago
Simplify -8x^2-3y+4x-2y^3+x^2-7x^3
rewona [7]

Answer:-7x(to the power of 2)-3y+4x-2y(to the 3rd power)-7x( to the third power)

Step-by-step explanation:

Collect like terms

5 0
3 years ago
Math again yay!...Ew math
Sliva [168]

Answer:

The graph of g(x) is wider.

Step-by-step explanation:

Parent function:

f(x)=x^2

New function:

g(x)=\left(\dfrac{1}{2}x\right)^2=\dfrac{1}{4}x^2

<u>Transformations</u>:

For a > 0

f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}

f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}

\begin{aligned} y =a\:f(x) \implies & f(x) \: \textsf{stretched/compressed vertically by a factor of}\:a\\ & \textsf{If }a > 1 \textsf{ it is stretched by a factor of}\: a\\  & \textsf{If }0 < a < 1 \textsf{ it is compressed by a factor of}\: a\\\end{aligned}

\begin{aligned} y=f(ax) \implies & f(x) \: \textsf{stretched/compressed horizontally by a factor of} \: a\\& \textsf{If }a > 1 \textsf{ it is compressed by a factor of}\: a\\  & \textsf{If }0 < a < 1 \textsf{ it is stretched by a factor of}\: a\\\end{aligned}

If the parent function is <u>shifted ¹/₄ unit up</u>:

\implies g(x)=x^2+\dfrac{1}{4}

If the parent function is <u>shifted ¹/₄ unit down</u>:

\implies g(x)=x^2-\dfrac{1}{4}

If the parent function is <u>compressed vertically</u> by a factor of ¹/₄:

\implies g(x)=\dfrac{1}{4}x^2

If the parent function is <u>stretched horizontally</u> by a factor of ¹/₂:

\implies g(x)=\left(\dfrac{1}{2}x\right)^2

Therefore, a vertical compression and a horizontal stretch mean that the graph of g(x) is wider.

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Simplify 5 square root 45
tangare [24]
I hope this helps you

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