Answer: 3600 seconds
Step-by-step explanation:
60 seconds in a minute
60 minutes in an hour
(60)(60) = 3600
Answer:
2.73 for each sock i believe
Step-by-step explanation:
Answer:
The probability that at most 1 car will require major engine repair next year is P=0.3392.
Step-by-step explanation:
This can be modeled as a binomial random variable, with n=22 and p=0.1.
The probability that exavtly k cars will require major engine repair next year is:
![P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}](https://tex.z-dn.net/?f=P%28x%3Dk%29%20%3D%20%5Cdbinom%7Bn%7D%7Bk%7D%20p%5E%7Bk%7D%281-p%29%5E%7Bn-k%7D)
Then, the probability that at most 1 car will require major engine repair next year is:
![P(x\leq1)=P(x=0)+P(x=1)\\\\\\P(x=0) = \dbinom{22}{0} p^{0}(1-p)^{22}=1*1*0.0985=0.0985\\\\\\P(x=1) = \dbinom{22}{1} p^{1}(1-p)^{21}=22*0.1*0.1094=0.2407\\\\\\P(x\leq1)=0.0985+0.2407\\\\P(x\leq1)=0.3392](https://tex.z-dn.net/?f=P%28x%5Cleq1%29%3DP%28x%3D0%29%2BP%28x%3D1%29%5C%5C%5C%5C%5C%5CP%28x%3D0%29%20%3D%20%5Cdbinom%7B22%7D%7B0%7D%20p%5E%7B0%7D%281-p%29%5E%7B22%7D%3D1%2A1%2A0.0985%3D0.0985%5C%5C%5C%5C%5C%5CP%28x%3D1%29%20%3D%20%5Cdbinom%7B22%7D%7B1%7D%20p%5E%7B1%7D%281-p%29%5E%7B21%7D%3D22%2A0.1%2A0.1094%3D0.2407%5C%5C%5C%5C%5C%5CP%28x%5Cleq1%29%3D0.0985%2B0.2407%5C%5C%5C%5CP%28x%5Cleq1%29%3D0.3392)
Answer:
18.7
Step-by-step explanation:
Answer:
the answer is C
Step-by-step explanation:
BABYSHARK