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Igoryamba
3 years ago
10

This is the last question please help

Mathematics
1 answer:
Ghella [55]3 years ago
7 0

Answer:

111

like add 14 to 18 to find y value

making 32

32+5 that's 37

multiply 3 and 37

111

that ur answer

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Do bonds reduce the overall risk of an investment portfolio? Let x be a random variable representing annual percent return for t
rjkz [21]

Answer:

COV (all stocks) = 0.55

COV (stocks and bonds) = 0.82

Step-by-step explanation:

Coefficient of Variation is used to measure variability.

It is defined as the ration of standard deviation and the mean.

It can be used to compare variability of two population or two samples.

Formula:

\text{Coefficient of Variation} = \displaystyle\frac{\text{Standard Deviation}}{\text{Mean}}

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}

where x_i are data points, \bar{x} is the mean and n is the number of observations.

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

x: 14, 0, 39, 25, 32, 27, 28, 14, 14, 15

Mean = \frac{208}{10} = 20.8

Standard~Deviation = \sqrt{\frac{1169.6}{9} } = 11.39

Coefficient~of~Variation = \frac{11.39}{20.8} = 0.55

y = 6, 2, 29, 17, 26, 17, 17, 2, 3, 5

Mean = \frac{124}{10} = 12.4

Standard~Deviation = \sqrt{\frac{924.4}{9} } = 10.13

Coefficient~of~Variation = \frac{10.13}{12.4} = 0.82%

Since coefficient of variation of x is less compared to y, thus it could be said bonds does not reduce overall risk of an investment portfolio.

6 0
3 years ago
Factorise x^2-y^2-2x+6y-8
Talja [164]
X^2 - y^2 - 2x + 6y - 8 
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<span>= [(x - 1) - (y - 3) ] [(x - 1) + (y - 3)] </span>
<span>= (x - 1 - y + 3) ( x - 1 + y - 3) </span>
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4 years ago
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2$ for each program
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At a football game three out of the first five student that arrived were wearing a jacket based on his information if 300 studen
WARRIOR [948]

Answer:

120 students students could be expected to not be wearing a jacket

Step-by-step explanation:

Based on this, we can work with the assumption that 3/5 of the students that entered the stadium were wearing jackets.

Given that the total population of students that attended the game is 300

This means that 3/5 of the 300 = 180 students.

180 students were estimated to be wearing jackets.

The number of students that were without jackets is 300 - 180 = 120 students

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