I think the correct answer is option D. It would be rotational symmetry that allows a figure to remain congruent as it rotates around a point in its plane. It also known as a radial symmetry. A figure which has this type of symmetry would look the same after rotating the figure by any angle. The degree of this symmetry would range from 2 to any positive whole integer. It depends on the number of distinct orientations that the figure would look the same. Examples are the shapes such as rectangles, circles, squares, stars, hexagon, pentagon and all regular polygons.
Answer: C
Step-by-step explanation:
12 x 6 x 4= 288 also do you do time4learning?
Answer:
D. 5267
Step-by-step explanation:
In the triangle XY and XZ are tangent to circle C. This means that the length has of XY and XZ are congruent.
So first you have to set the equations to each other to find what b equals to.
85b+83=91b-283
Add 283 to both sides
85b+366=91b
Subtract 85b on both sides
366=6b
Divide by 6
B=61.
Then you substitute 61 as b in the equation for XY.
85b+83
85(61)+83
5185+83
5268
Answer:
<h2>
<em>3</em></h2>
<em>Expl</em><em>anation</em><em>:</em>
<em>![\sqrt[a]{ {x}^{n} } = {x}^{ \frac{n}{a} } \\ \sqrt[7]{ {53}^{3} } = {(53}^{3} ) {}^{ \frac{1}{7} } \\ \: \: \: \: \: \: \: \: \: \: \: = {53}^{ \frac{3}{7} } \\ comparing \: with \: {53}^{ \frac{a}{b} } \\ a = 3](https://tex.z-dn.net/?f=%20%5Csqrt%5Ba%5D%7B%20%7Bx%7D%5E%7Bn%7D%20%7D%20%20%3D%20%20%7Bx%7D%5E%7B%20%5Cfrac%7Bn%7D%7Ba%7D%20%7D%20%20%5C%5C%20%20%5Csqrt%5B7%5D%7B%20%7B53%7D%5E%7B3%7D%20%7D%20%20%3D%20%20%7B%2853%7D%5E%7B3%7D%20%29%20%7B%7D%5E%7B%20%5Cfrac%7B1%7D%7B7%7D%20%7D%20%20%5C%5C%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%3D%20%20%7B53%7D%5E%7B%20%5Cfrac%7B3%7D%7B7%7D%20%7D%20%20%5C%5C%20comparing%20%5C%3A%20with%20%5C%3A%20%20%7B53%7D%5E%7B%20%5Cfrac%7Ba%7D%7Bb%7D%20%7D%20%20%5C%5C%20a%20%3D%203)
</em>
<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>
=(4-x^2)(a+b)
=(2^2-x^2)(a+b)
=(x+2)(x-2)(a+b)
I think it hopefull to you
