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lukranit [14]
3 years ago
9

There are 75 students in classes A and B altogether. There are 61 students in classes A and C altogether. The ratio of the numbe

r of students in Class B to Class C is 5:3. How many students are there in Class A?
Mathematics
2 answers:
morpeh [17]3 years ago
6 0

Answer:

A = 40

Step-by-step explanation:

A+B = 75

A+C = 61

Subtract

A+B = 75

-A-C = -61

----------------------

B-C = 14

B:C

5:3

for every 5B there are 3C

Replace B with 5/3 C

5/3C-C = 14

2/3C = 14

C = 21

A+C = 61

A +21 = 61

A = 40

Bezzdna [24]3 years ago
3 0

Answer:

40

Step-by-step explanation:

A +  B=75

A + C = 61

B = 5/3 *C

A+C * 5/3 = 75 then we got the answer

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Find the basis for the subspace of R^3 spanned by S = {(81, 63, 12), (27, 21, 4), (9, 7, 1)). {(0, 0, 1), (9, 0, 0), (0, 7, 0);
Romashka-Z-Leto [24]

Answer with explanation:

A basis of a subspace in R³ is the set of vectors that spans the subspace means the set of vectors, and is linearly  independent.

The meaning of span is if any set of vectors can be written as linear combination of other vector.

For example , {a, b,c}, {p,q,r} and {x,y,z} are three set of vectors.

If ,{a,b,c} can be wriiten as {pm +x n, q m+y n, r m+z n}, then we say that  {a,b,c} spans the set of vectors.

1.

S={(81, 63, 12), (27, 21, 4), (9, 7, 1)}

Writing the set of vectors in matrix form

  \left[\begin{array}{ccc}81&63&12\\27&21&4\\9&7&1\end{array}\right]\\\\R_{2} \Rightarrow 3R_{2}-R_{1}\\\\R_{3} \Rightarrow 9R_{3}-R_{1}\\\\\left[\begin{array}{ccc}81&63&12\\0&0&0\\0&0&0\end{array}\right]

→Basis of S=1

As all the three vectors are linearly dependent.So, Basis=1.

2.

{(0, 0, 1), (9, 0, 0), (0, 7, 0)}

If you write these three vectors in matrix form , all the three vectors are Linearly Independent.Any of the one vectors can't be written as a linear combination of other

So, Basis =3

3.

{(1, 0, 0), (0, 0, 1), (0, 7, 0)}

All the three vectors are Linearly Independent.

So, Basis=3

4. {(0, 0, 1), (9,7, 0)}

These two vectors can't be written as a linear combination of other.So these two vectors are Independent.So,

Basis=2

5. {9,0,0), (0,7, 0)}

These two vectors can't be written as linear combination of each other.So these two vectors are Independent.So,

Basis=2

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