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lukranit [14]
3 years ago
9

There are 75 students in classes A and B altogether. There are 61 students in classes A and C altogether. The ratio of the numbe

r of students in Class B to Class C is 5:3. How many students are there in Class A?
Mathematics
2 answers:
morpeh [17]3 years ago
6 0

Answer:

A = 40

Step-by-step explanation:

A+B = 75

A+C = 61

Subtract

A+B = 75

-A-C = -61

----------------------

B-C = 14

B:C

5:3

for every 5B there are 3C

Replace B with 5/3 C

5/3C-C = 14

2/3C = 14

C = 21

A+C = 61

A +21 = 61

A = 40

Bezzdna [24]3 years ago
3 0

Answer:

40

Step-by-step explanation:

A +  B=75

A + C = 61

B = 5/3 *C

A+C * 5/3 = 75 then we got the answer

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Round <br> 653<br> ,<br> 500<br> 653,500653, comma, 500 to the nearest thousand.
Jlenok [28]

Answer:

Do you mean to round the number 653,500,653,500,653,500? Or do you mean to round the number 653,500? If so, for 653,500, the digit in the thousand's place is 5, so it's already rounded to the nearest thousands place.

Step-by-step explanation:

5 0
3 years ago
Performance task A parade route must start And and at the intersections shown on the map. The city requires that the total dista
Flauer [41]

Answer:

  A: the proposed route is 3.09 miles, so exceeds the city's limit

Step-by-step explanation:

The length of the route in grid squares can be found using the Pythagorean theorem on the two parts of the route. Let 'a' represent the length of the route to the park from the start, and 'b' represent the route length from the park to the finish. Then we have (in grid squares) ...

  a^2 = (12-6)^2 +3^2 = 45

  a = √45 = 3√5

and

  b^2 = (6 -2)^2 +4^2 = 32

  b = √32 = 4√2

Then the total length, in grid squares, is ...

  3√5 + 4√2 = 6.7082 +5.6569 = 12.3651

If each grid square is 1/4 mile, then 12.3651 grid squares is about ...

  (12.3651 squares) · (1/4 mile/square) = 3.0913 miles

The proposed route is too long by 0.09 miles.

5 0
3 years ago
Which equation describes the circle having center point (3,7) and the radius r=4 in Standard form
Annette [7]

The equation of circle in standard form is (x - 3)^2 + (y - 7)^2 = 16

<h3><u>Solution:</u></h3>

Given that circle having center point (3,7) and the radius r = 4

To find: equation of circle in standard form

<em><u>The equation of circle is given as:</u></em>

(x - h)^2 + (y - k)^2 = r^2

Where center (h,k) and radius r units

Given that center point (h , k) = (3, 7) and radius r = 4 units

Substituting the values in above equation of circle,

(x - 3)^2 + (y - 7)^2 = 4^2\\\\(x - 3)^2 + (y - 7)^2 = 16

Thus the equation of circle in standard form is (x - 3)^2 + (y - 7)^2 = 16

6 0
3 years ago
What is the product of these?
Phoenix [80]
<h2><u>96√5</u></h2>

8 × 4 = 32

√3 ×√15 = √45

√75 = √9 × √5

√9 = 3

√75 = 3√5

32 × 3√5 = 96√5

3 0
3 years ago
Please help to find an explicit formula for calculating the sum Mn
defon

The explicit formula for calculating the sum is

S_N=\frac{n(n-1)}{2} \cdot\frac{n(n+1)}{2}

The sum of the nth term of a sequence is expressed as;

S_n=\frac{n}{2}(2a+(n-1)d)

a is the first term

d is the common difference

n is the number of terms

For the sequence  0 + 1 + 2 + 3  +...

S_n=\frac{n}{2}(2(0)+(n-1)1)\\S_n= \frac{n}{2}(n-1)\\S_n= \frac{n(n-1)}{2}

Similarly for the sequence:

1 + 2+ 3 + 4+...

S_n=\frac{n}{2}(2(1)+(n-1)1)\\S_n= \frac{n}{2}(2+n-1)\\S_n= \frac{n(n+1)}{2}

Taking the product of the sum to get the explicit formula for calculating the sum

S_N=\frac{n(n-1)}{2} \cdot\frac{n(n+1)}{2}

Learn more here: brainly.com/question/24547297

8 0
2 years ago
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