A 90 degree clockwise rotation will leave the sides with the same length,
will leave the angles the same , it will only change the position of the triangle.
The rotated triangle will be congruent to the original triangle
Answer:
12 Hours
Step-by-step explanation:
So it says he writes 8 pages in 2 hours. Which would mean he takes an hour to write 4 pages. You divide 48 pages by 4 hours and you get 12.
When competing the square, you want to have
at the end, and using the fact that the x term and coefficient are really
, we see that the third option is the most efficient way to start
1. 8r + 4 = 10 + 2r
-4 -4
8r = 6 + 2r
-2r -2r
6r = 6
R= 1
2. -2(x + 3) = 4x - 3
-2x - 6 = 4x - 3
+3 +3
-2x -3 = 4x
+2x +2x
-3 = 6x
————-
6 6
-1/2 = x
3. 5 + 3(q - 4) = 2(q + 1)
5 + 3q - 12 = 2q + 2
-7 + 3q = 2q + 2
+7 +7
3q = 2q + 9
-2q -2q
Q = 9
4. 7x - 4 = -2x + 1 + 9x - 5
7x - 4 = 7x - 4
-7x -7x
-4 = -4
+4 +4
0 = 0
Infinite answers
5. 8x + 6 - 9x = 2 - x -15
-x +6 = - 13 - x
+ x +x
6 = -13
No solution
1.)
=(x-8i)(x+8i)
x^2+8ix-8ix-64i^2
x^2-64i^2
x^2-64(-1)
x^2+64
2.)
=(4x-7i)(4x+7i)
16x^2+28ix-28ix-49i^2
16x^2-49i^2
16x^2-49(-1)
16x^2+49
3.)
=(x+9i)(x+9i)
x^2+9ix+9ix+81i^2
x^2+18ix+81(-1)
x^2+18ix-81
4.)
=(x-2i)(x-2i)
x^2-2ix-2ix+4i^2
x^2-4ix+4(-1)
x^2-4ix-4
5.)
=[x+(3+5i)]^2
(x+5i+3)^2
(x+5i+3)(x+5i+3)
x^2+5ix+3x+5ix+25i^2+15i+3x+15i+9
x^2+6x+10ix+30i+25i^2+9
x^2+6x+10ix+30i+25(-1)+9
x^2+6x+10ix+30i-25+9
x^2+6x+10ix+30i-16
Hope this helps :)