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2 years ago

7

para preparar 10 litros de pintura naranja se necesitan 6 litros de pintura amarilla y 4 litros de pintura roja que cantidad de

pintura amarilla y roja se necesitan para obtener 15 litros de pintura naranja

1 answer:

nikdorinn [45]2 years ago

8 0

Someone translate please

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Leatherbound Stores, Inc., rejects a shipment of goods that does not conform to its contract with Cowhide Corporation, but is un

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Answer:

resell, return, or store the goods

Step-by-step explanation:

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2 years ago

If X is a normally distributed random variable with mean .30 and standard deviation .06 : (draw appropriate diagrams) a) Find P(

Ierofanga [76]

Answer:

0.34 x 0.38

=0.1292

Step-by-step explanation:

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2 years ago

g A shopping center includes a grocery store and a drug store. One%E2%80%8B afternoon, a total of 200 people visited the shoppin

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Answer:

a) 179 people shopped at the grocery store or the drug store.

b) 21 people shopped at neither the grocery store nor the drug store

Step-by-step explanation:

I am going to treat these events as Venn sets.

I am going to say that:

Set A: Shopped at the grocery store

Set B: Shoped at the drug store.

121 shopped at the grocery store:

This means that $A = 121$

91 shopped at the drug store:

This means that $B = 91$

33 shopped at both businesses.

This means that $A \cap B = 33$

a) How many people shopped at the grocery store or the drug store?

This is

$A \cup B = A + B - (A \cap B)$

With the values given in the exercise.

$A \cup B = A + B - (A \cap B) = 121 + 91 - 33 = 179$

179 people shopped at the grocery store or the drug store.

b) How many people shopped at neither the grocery store nor the drug store?

179 of 200 shopped in at least one. So 200 - 179 = 21 shopped at neither.

21 people shopped at neither the grocery store nor the drug store

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2 years ago

mr. Johnson borrowed $750 for one year he has to pay 6% simple interest how much interest will he pay

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Answer:

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Step-by-step explanation:

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2 years ago

An observer (O) spots a plane flying at a 42° angle to his horizontal line of sight. If the plane is flying at an altitude of 15

NeTakaya

Answer:

D. 22,417 feet

Step-by-step explanation:

Fine the diagram in the attachment for proper elucidation. Using the SOH, CAH, TOA trigonometry identity to solve for the distance (x) from the plane (P) to the observer (O), the longest side x is the hypotenuse and the side facing the angle of elevation is the opposite.

Hypotenuse = x and Opposite = 15,000feet

According to SOH;

$sin 42^0 = \frac{Opposite}{Hypotenuse} \\\\Sin42^0 = \frac{15000}{x}\\ \\x = \frac{15000}{sin42^0}\\\\ \\$

$x = \frac{15000}{ 0.6691} \\\\x = 22,417 feet$

Hence the distance (x) from the plane P to the observer O is approximately 22,417 feet

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3 years ago