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igomit [66]
3 years ago
8

An astronaut in deep space is at rest relative to a nearby space station. The astronaut needs to return to the space station. A

student makes the following claim: “The astronaut should position her feet pointing away from the space station. Then, she should repeatedly move her feet in the opposite direction to each other. This action will propel the astronaut toward the space station.” Is the student’s claim correct? Justify your selection.
A.) Yes. The astronaut’s feet exert a force away from the space station, creating an equal and opposite force that will accelerate the astronaut toward the space station.

B.) Yes. The astronaut’s feet will have a velocity that is transferred to her center of mass, accelerating the astronaut toward the space station.

C.) No. The astronaut’s feet are not exerting a force on another object, so there is no external force to accelerate the astronaut toward the space station.

D.) No. The astronaut would move away from the space station, not toward it, since her feet are pointed away from the space station.
Physics
2 answers:
Paha777 [63]3 years ago
7 0

Answer:

what u

Explanation:

know about rolling down in the deep when ue brain goes du m u can call that mental freeze when people talk to much puy that shi t on slow motion

Marta_Voda [28]3 years ago
4 0
Its A ig , just my guess
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Ground-based radio telescopes can collect data from distant objects in space
Butoxors [25]

Answer:

A.  during the day or night and in any weather conditions.

Explanation:

Ground-based radio telescopes can be used to collect data from distant objects in space during the day or night in any weather condition.

They do not depend or are they affected by weather and they pass well through them.

  • Telescopes are devices used to obtain information about distant bodies usually astronomical in nature.
  • Optical telescopes use the visible range of light and they are overwhelmed by the sun during the day.
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6 0
3 years ago
Ricardo and Jane are standing under a tree in the middle of a pasture. An argument ensues, and they walk away in different direc
Lapatulllka [165]

Answer:

a)     d = 30.79 m , b) θ = -22.4° ,   θ = 22.4 South of East

Explanation:

The easiest way to solve problems with vectors is to use their components, for this the East-West direction coincides with the x-axis and the North-South direction coincides with the y-axis

Let's use the index for / Ricardo and the index for Jane, let's break down the displacements

Richard

X axis

      x₁ = 26.0 sin (60)

      x₁ = -22.52 m

Y Axis  

     y₁ = 26.0 cos 60

     y₁ = 13 m / s

Jane

X axis

       x₂ = 16.0 cos (180 +30)

       x₂ = -13.85 m

Y Axis  

        y₂ = 16.0 sin (180 + 30)

        y₂ = - 8.0 m

Now we can use Pythagoras' theorem to find the distance between them

         d = √ [(x₂ -x₁)² + (y₂ -y₁)²]

         d = √ [(-13.85 + 22.52)² + (-8 -13)²]

         d = 30.79 m

Let's use trigonometry to enter the address

         tan θ = Δy / Δx

         θ = tan⁻¹ Δy / Δx

         θ = tan⁻¹ (-13.85 + 22.52) / (-8 - 13)

         θ = tan⁻¹ (-8.67 / 21)

         θ = -22.4°

The negative sign indicates that the angle is measured from the axis clockwise.

In the form of cardinal s point is

     θ = 22.4 South of East

4 0
4 years ago
How does current flow in a standard DC circuit?
KATRIN_1 [288]

Answer:

A

Explanation:

4 0
3 years ago
A cheetah accelerates from 15 m/s to 30 m/s in 3.0s what is the cheetahs acceleration
Amanda [17]
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acceleration=15/3
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5 0
3 years ago
Read 2 more answers
You have arrived at the scene of a two car accident. You know the following pieces of information:
Pani-rosa [81]

The initial velocity of car 1 is 20 m/s to the right

The initial velocity of car 2 is zero

The final velocity of car 2 is 10 m/s to the right

Explanation:

We can solve the problem by using the law of conservation of momentum: the total momentum of the system must be conserved before and after the collision.

Therefore, we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where:

m_1 = 2000 kg is the mass of the first car

u_1 is the initial velocity of the first car

v_1 = 10 m/s is the final velocity of the first car (taking right as positive direction)

m_2 = 2000 kg is the mass of the second car

u_2 = 0 is the initial velocity of the second car

v_2 is the final velocity of the second car

We also know the initial momentum of car 1, which is

p_1 =40,000 kg m/s

And since momentum is the mass times the velocity, we find the initial velocity of car 1:

u_1 = \frac{p_1}{m_1}=\frac{40,000}{2,000}=20 m/s

with a positive sign, since the direction is to the right.

Now we can re-arrange the previous equation and solve for v2, the final velocity of car 2:

v_2 = \frac{m_1 u_1 -m_1 v_1}{m_2} = \frac{(2000)(20)-(2000)(10)}{2000}=10 m/s

And since the sign is positive, the direction is the same as the initial direction of car 1, so to the right.

Learn more about momentum here:

brainly.com/question/7973509  

brainly.com/question/6573742  

brainly.com/question/2370982  

brainly.com/question/9484203  

#LearnwithBrainly

8 0
3 years ago
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