The object will sail away in a straight line ... continuing in the same direction it was going when the centripetal force stopped.
Si es verdad no entiendo ni madres
Answer:
(a) 
(b) 
(c) 
Solution:
As per the question:
Mass of Earth, 
Mass of Moon, 
Mass of Sun, 
Distance between the earth and the moon, 
Distance between the earth and the sun, 
Distance between the sun and the moon, 
Now,
We know that the gravitational force between two bodies of mass m and m' separated by a distance 'r' is given y:
(1)
Now,
(a) The force exerted by the Sun on the Moon is given by eqn (1):



(b) The force exerted by the Earth on the Moon is given by eqn (1):



(c) The force exerted by the Sun on the Earth is given by eqn (1):



Answer:
v' = 2.4 m/s
Explanation:
Given that,
Mass of one skater, m = 60 kg
Mass of the other's skater, m' = 60 kg
The two skaters push off each other. After the push, the smaller skater has a velocity of 3.0 m/s.
When there is no external force acting on a system, the momentum remains conserved. It means initial momentum is equal to the final momentum. Let v' is the velocity of the larger skater.
mv = m'v'

So, the velocity of the larger skater is 2.4 m/s.
Answer:
E=6.91 N/C
Explanation:
Given that
Linear Charge density ,λ = 5 nC/m
Distance ,R= 13 m
We know that formula for long wire to find electric field

E=Electric field
R=Distance
εo=8.85 x 10⁻¹² C²/N.m²
λ=Linear Charge density
Now by putting the values

E=6.91 N/C
Therefore the electric filed at distance 13 m will be 6.91 N/C