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KATRIN_1 [288]
4 years ago
7

Suppose 30.4 mol of krypton is in a rigid box of volume 46 cm3 and is initially at temperature 438.28°C. The gas then undergoes

isobaric heating to a temperature of 824°C. (a) What is the final volume of the gas? (b) It is then isothermally compressed to a volume 24.3cm3; what is its final pressure? cm (a) Answer part (a) Answer part (b) (b) Pa
Physics
1 answer:
Mariana [72]4 years ago
8 0

Answer:

Explanation:

Initial volume v₁ =46 x 10⁻⁶ m³

Initial temperature T₁ = 438.28 + 273 = 711.28 K

Initial pressure P₁ = nRT₁ / v₁

= 30.4 x8.3 x 711.28 / (46 x 10⁻⁶ )

= 3901.5 x 10⁶ Pa

Final temperature T₂ = 824 + 273 = 1097 K

Final volume V₂ =?

For isobaric process

v₁ / T₁ = V₂ / T₂

V₂ = V₁ X T₂ /T₁

= 46 X 10⁻⁶ X 1097/ 711.28

= 70.94 X 10⁻⁶ m³ = 70.94 cm³

b ) For isothermal change

P₁ V₁ = P₂V₂

P₂ = P₁V₁ / V₂

= 3901.5 X 10⁶ X 46 / 24.3

7385.55  X 10⁶ Pa.

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If it takes 600 N of force to move a stalled truck 30 meters and you do it in 15
gogolik [260]

Your power is 1200 watts ⇒ answer D

Explanation:

Power is the rate of change of the work done

→ Power = Work done ÷ time

→ Work = Force × distance

→ Power = (Force × distance) ÷ time

It takes 600 N of force to move a stalled truck 30 meters and you

do it in 15  seconds

→ Force = 600 N

→ Distance = 30 meters

→ Time = 15 seconds

Substitute these values in the rule above

→ Power = (600 × 30) ÷ 15

→ Power = 18000 ÷ 15

→ Power = 1200 watts

Your power is 1200 watts

Learn more:

You can learn more about power in brainly.com/question/7956557

#LearnwithBrainly

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3 years ago
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An astronaut is planning a trip to a newly-discovered planet. According to 2 points
rodikova [14]

Answer:

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3 years ago
A rod (length = 2.0 m) is uniformly charged and has a total charge of 5.0 nC. What is the electric potential (relative to zero a
Ksenya-84 [330]

Answer:

The electric potential is  V  =  15.6 V

Explanation:

From the question we are told that

   The length  of the rod is  L =  2.0 \ m

     The total charge of the rod is  q =5.0 nC = 5.0*10^{-9} C

      The length from the center is  d =  3.0 \ m

The diagram illustrating the setup for this question is shown on the first uploaded image

From the diagram the potential at point  A  dl is mathematically represented as

         dV  =  K  \frac{dq}{l}

Where K is the coulomb constant with a value  K  = 9*10^9 \   Nm^2 /C^2

where q is the charge in charge  the rod relative to its distance from A  is mathematically represented as

         dq =  \frac{q}{L}  dl

This a small unit length of the rod

So         V = \frac{q}{L}  \int\limits^4_2  {\frac{dl}{l} } \,

        =>   V =  k\frac{q}{L}  ln [\frac{4}{2} ]

              V =  k\frac{q}{L}  ln2

Substituting values

                V  =  9* 10^9  *  \frac{5*10^{-9}}{2} * ln 2

                 V  =  15.6 V

         

7 0
4 years ago
A car wheel turns through 277° in 10.7 s. Calculate the angular speed of the wheel.
slava [35]

Answer:

The angular speed of the wheel is 0.452 rad/s

Explanation:

The angle through which the car wheel turns, Δθ = 277° = 277/360 × 2·π radian

The time it takes for the car wheel to turn, Δt = 10.7 s

The angular speed, ω is given by the following equation;

Angular \ speed = \dfrac{Change \ in \ angular \ rotation }{Change \ in \ time} = \dfrac{\Delta \theta}{\Delta t}

Substituting the known values for Δθ and Δt gives;

Angular \ speed = \dfrac{\dfrac{277 ^{\circ}}{360 ^{\circ }  }  \times 2 \times \pi \ radian}{10.7 \ seconds} \approx 0.452 \ rad/s

The angular speed of the wheel = 0.452 rad/s

3 0
3 years ago
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