Answer:
Induced emf in the loop is 0.02208 volt.
Induced current in the loop is 0.0368 A.
Explanation:
Given that,
Area of the single loop, 
The initial value of uniform magnetic field, B = 3.8 T
The magnetic field is decreasing at a constant rate, 
(a) The induced emf in the loop is given by the rate of change of magnetic flux.
(b) Resistance of the loop is 0.6 ohms. Let I is the current induced in the loop. Using Ohm's law :
Hence, this is the required solution.
<span>It gains an electron.</span>
Answer:
Lens and the virtual image was the image distance. Error was made when measuring the distances and determining values that were reasonable for focal length, so this error was accounted for when calculating the focal length by adding or subtracting uncertainties from the values.Plane mirrors, convex mirrors, and diverging lenses can never produce a real image. A concave mirror and a converging lens will only produce a real image if the object is located beyond the focal point (i.e., more than one focal length away). 5.
Using the kinematic equation below we can determine the distance traveled if t=2, a=7.4m/s^2. First we must determine the final velocity:
Now we will determine the distance traveled:
Therefore, the drag racer traveled 81.83 meters in 2 seconds.
The magnitude of a point charge is 0.189 x 10⁻⁹C.
<h3>Steps</h3>
We have stated that the point charge's electric field is E=2.5 N/C.
Distance from point charge R = 51 cm = 0.51 m
We are aware that the electric field resulting from a point charge is given as E = 1 / 4π∈₀ × Q / R²
so 2.5 = 9 x 10⁹ Q/ 0.68²
The magnitude of a point charge is 0.189 x 10⁻⁹C.
The electric force per unit charge is referred to as the electric field. It is assumed that the field's direction corresponds to the force it would apply to a positive test charge.
From a positive point charge, the electric field radiates outward, and from a negative point charge, it radiates in.
learn more about electric field here
brainly.com/question/14372859
#SPJ4
