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3 years ago

Consider the sequence:

Mathematics

1 answer:

Assoli18 [71]3 years ago

7 0

Answer:

ans 12

Step-by-step explanation:

first term(a)=89

common difference(d)=7

we know,

tn=a+(n-1)d

t12=89+(12-1)(-7)

t12=89+11*(-7)

t12=89-77

t12=12

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The profit function for a new product is given by p(x) = -4x^2+28x-40, where x is the number sold in thousands. How many items m

Ivenika [448]

The break even point is when profit is equal to zero, or in this case when p(x)=0

4x^2-28x+40=0

4(x^2-7x+10)=0

4(x^2-2x-5x+10)=0

4(x(x-2)-5(x-2))=0

4(x-5)(x-2)=0

So the break even points are when x=2 and 5, which is when 2000 and 5000 units are sold.

3 0

3 years ago

Karen is applying for the nursing school at the University of Davis. Before applying, she received a breakdown of the tuition an

Sidana [21]

Answer:

Step-by-step explanation:

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2 years ago

A cube-shaped aquarium has edges that are 3 feet long and is filled with water that has a density of 62 lbs/ft3 Should the aquar

Sunny_sXe [5.5K]

Given:

There are given the edge of the cube-shaped aquarium has 3 feet.

Explanation:

To find the value, we need to use the volume of the cube formula:

So,

From the formula of volume:

$V=a^3$

Where

a represents the value of edge.

So,

Put the value of edge into the above formula:

Then,

$\begin{gathered} V=a^3 \\ V=3^3 \\ V=27cube\text{ feet} \end{gathered}$

Now,

The water has a density of 62 pounds per cube foot.

According to the question:

If the weight of 1 cubic foot of water is 62 pounds, then the weight of 27 cube feet water is:

$62\times27=1674pound$

Final answer:

Hence, the water weight of the full aquarium is 1674 pounds, and the table only susupports00 pounds. So the table cannot hold the aquarium.

And,

No, the density of water would not change.

6 0

1 year ago

Circumference, radius, slant height, lateral area, and surface area are measurements of a cone. Given two of the measurements, f

USPshnik [31]

Answer:

LA = 21.7 ft²; C = 18.8 ft; h = 2.3 ft
h = 8 in; r = 7 in; SA = 330.1 in²

Step-by-step explanation:

Applicable relations are ...

C = 2πr . . . . . . . r = radius, C = circumference

LA = 1/2·Ch . . . . h = slant height, LA = lateral area

SA = πr² +LA . . . SA = total surface area

1. Given r and SA, we can find the other measures as ...

LA = SA -πr² = 50 ft² -π(3 ft)² ≈ 21.7 ft²

C = 2πr = 2π(3 ft) ≈ 18.8 ft

h = 2·LA/C ≈ 2·21.7 ft²/(18.8 ft) ≈ 2.3 ft

(Please note that for calculations using intermediate results, we used the full-precision values of those results, not the rounded ones. Rounding is always the last operation. Please note, too, that we have used a value for π sufficient to ensure accuracy in all the digits shown here.)

2. Given C and LA, we can find the other measures as ...

h = 2·LA/C = 2(176 in²)/(44 in) = 8 in

r = C/(2π) = (44 in)/(2π) ≈ 7.0 in

SA = LA +πr² = LA +rC/2 ≈ 176 in² +(7.0 in)(44 in)/2 ≈ 330.1 in²

4 0

3 years ago

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RUDIKE [14]

Answer:

Step-by-step explanation:

I put it in my calculator

3 0

3 years ago

Read 2 more answers