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Zinaida [17]
3 years ago
9

In a factory, the chance that a certain machine works without overheating in the morning is 50%. If it runs smoothly all morning

, then there is an 85% chance that it will continue for the rest of the day and a 15% chance that it will stop due to overheating. What is the probability that on a given day it will work in the morning and overheat later on?
Mathematics
1 answer:
sammy [17]3 years ago
7 0
Let's imagine that we turn the machine on 100 times. (this will make the percent conversion easier)

the chance that works in the morning is 50%  of 100 so it will work 50 times.

the chance that it will then continue for the rest of the day is 15% so 15%*50 (the number of times it worked), which is 7.5 times.

our times actually represented percent, so the answer is : 7.5%!

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A student performed the following steps to find the solution to the question x^2 - 2x - 15 = 0. Where did the student go wrong?
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Answer:

D  In step 3

Step-by-step explanation:

Given polynomial:  x² - 2x - 15 = 0

Step 1:  factor the polynomial ⇒ (x + 3)(x - 5) = 0

Step 2:  x + 3 = 0  and  x - 5 = 0

Step 3:  x = -3  and x = 5

x - 5 = 0

Add 5 to both sides:

⇒ x - 5 + 5 = 0 + 5

⇒ x = 5

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2 years ago
Which ordered pair is a solution of the given system of equations <br>{x+2y=6<br> {x-y=3
Ainat [17]
The pair (4,1) is the solution.
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Is (0,0) a solution to this system ?
Akimi4 [234]
The answer is choice B

The point (0,0) makes the first inequality true since
y >= x^2-4
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0 >= 0
is true

However, the point (0,0) does not make the second inequality true
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3 0
3 years ago
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svetoff [14.1K]

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5 0
3 years ago
An object dropped from a height of 600 feet has a height, h(t), in feet after t seconds have elapsed, such that h(t)=600−16t2. E
Sliva [168]

Answer:

The function t(h) is t(h) = \sqrt{\frac{600-h}{16}}

The time to reach a height 250 feet is 4.68 seconds

Step-by-step explanation:

* Lets explain how to solve this problem

- An object dropped from a height of 600 feet has a height, h(t), in feet

  after t seconds have elapsed, such that

  h(t) = 600 − 16 t²

- We need to express t is a function of the height h

- To do that lets find t in terms of h

∵ h = 600 - 16 t²

- Add 16 t² to both sides

∴ 16 t² + h = 600

- Subtract h from both sides

∴ 16 t² = 600 - h

- Divide both sides by 16

∴ t² = \frac{600-h}{16}

- Take √ for both sides

∴ t = \sqrt{\frac{600-h}{16}}

∴ t(h) = \sqrt{\frac{600-h}{16}}

* The function t(h) is t(h) = \sqrt{\frac{600-h}{16}}

- Now lets find the time of the object to reach a height 250 feet

∵ t(h) = \sqrt{\frac{600-h}{16}}

∵ h = 250

∴ t(250) = \sqrt{\frac{600-250}{16}}

∴ t(250) = 4.68 seconds

* The time to reach a height 250 feet is 4.68 seconds

5 0
3 years ago
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