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4 years ago

Write an equation of the line that passes through the given points. (-1,7) (3,-9)

Mathematics

2 answers:

MA_775_DIABLO [31]4 years ago

8 0

Answer:

y=-4x+3

Step-by-step explanation:

If we wanted to write an equation for the line in slope intercept form, than first we would need to find the slope. We can do this by using the equation y2-y1/x2-x1=m or slope. Slope intercept form can be written as y=mx+b.

-9-7=-16

3--1 or 3+1=4

Now we can divide.

-16/4=-4

The slope is -4

Now we have to find the y intercept, or b.

To do so, insert all of the place values we know into the equation and solve for b.

7=4+b

3=b

So the y-intercept is 3.

Finally, we can write the complete equation as y=-4x+3

Hope this helps! :D

Novay_Z [31]4 years ago

5 0

Answer:

x=13

hope you do well

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bija089 [108]

Answer:

The null hypothesis μ=4.0 could not be rejected.

Step-by-step explanation:

In this problem we have to perform a hypothesis test of the mean, with s.d. of the population unknown.

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This sample has a mean of 4.033 and a standard deviation of 0.061.

The null and alternative hypothesis are:

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4 years ago

Can somebody please help me ? I gotta turned this in 10 minutes .

Arturiano [62]

Answer:

y = $-\frac{1}{3}x-\frac{2}{3}$

Step-by-step explanation:

Let the equation of the line is,

y = mx + b

m = Slope of the line

b = y-intercept

Since, slope of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by,

m = $\frac{y_2-y_1}{x_2-x_1}$

Since, the given line passes through two points (-5, 1) and (4, -2)

Slope of the line 'm' = $\frac{1+2}{-5-4}$ = $-\frac{1}{3}$

Equation of the line will be,

y = $-\frac{1}{3}x+b$

Since, this line passes through (4, -2),

-2 = $-\frac{4}{3}+b$

b = $\frac{4}{3}-2$

b = $-\frac{2}{3}$

Therefore, equation of the line will be,

y = $-\frac{1}{3}x-\frac{2}{3}$

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LekaFEV [45]

$\huge\bold{To\:find :}$

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$\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}$

The value of $x°$ is 150°. ✅

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

We know that,

$\sf\purple{Sum\:of\:angles\:on\:a\:straight\:line\:= \:180°}$

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Substituting the value of '' $y°$ " in the above equation,

➪ $x°$ = 99° + 51°

➪ $x°$ = 150°

$\sf\red{Therefore, \:the\: value \:of \:x°\: is \:150°.}$

Note:-

Kindly refer to the attached file.

${\boxed{\mathcal{\blue{Happy\:learning .}}}}$

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