All categories

3 years ago

What is the scale factor

Mathematics

2 answers:

seraphim [82]3 years ago

8 0

Answer:

The scale factor is the ratio of the length of a side of one figure to the length of the corresponding side of the other figure.

Step-by-step explanation:

SVETLANKA909090 [29]3 years ago

3 0

AD is 9 units long

A’D’ is 3 units long.

Scale factor is A’D’ / AD

Scale factor = 3/9 = 1/3

You might be interested in

The denominator of a fraction is 5 more than twice the numerator. If both numerator and denominator are decreased by 7, the simp

Ugo [173]

Answer:

numerator is 10

denominator is 25

Step-by-step explanation:

let x be the numerator

let y be the denominator

write 2 equations:

y = 5 + 2x

$\frac{x-7}{y-7}$ = $\frac{1}{6}$

y is already isolated in the first equation, substitute into the second equation:

$\frac{x-7}{5+2x-7}$ = $\frac{1}{6}$

simplify:

$\frac{x-7}{2x-2}$ = $\frac{1}{6}$

cross multiply:

2x - 2 = 6(x - 7)

simplify:

2x - 2 = 6x - 42

subtract 2x:

-2 = 4x - 42

add 42:

4x = 40

divide by 4:

x = 10

plug in 10 for x in the first equation:

y = 5 + 2(10)

y = 5 + 20

y = 25

numerator is 10

denominator is 25

6 0

3 years ago

Solve 3,125 = 5–10 + 3x

AlladinOne [14]

Answer:3130/3

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The larger of two numbers is 10 less than twice the smaller number. If the sum of the two numbers is 38, find the two numbers.

scoundrel [369]

Answer: lesser number is 16 greater number 22

Step-by-step explanation:

4 0

3 years ago

Please help! Will mark the brainliest!

sesenic [268]

The domain is the set of all possible x-values which will make the function valid.
$f(x) = \frac{3}{x-2} \ \ \ \ , \ g(x) = \sqrt{x-1}$
For the given function :
The denominator of a fraction cannot be zero
The number under a square root sign must be Non negative

(a)

(1) The domain of f ⇒⇒⇒ R - {2}

Because ⇒⇒⇒ x - 2 = 0 ⇒⇒⇒ x = 2

(2) The domain of g ⇒⇒⇒ [1,∞)
Because: x - 1 ≥ 0 ⇒⇒⇒ x ≥ 1

(3) $f + g = \frac{3}{x-2} + \sqrt{x-1}$
The domain of (f+g) ⇒⇒⇒ [1,∞) - {2}
because: x-2 = 0 ⇒⇒⇒ x = 2 and    x - 1 ≥ 0 ⇒⇒⇒ x ≥ 1

(4) $f - g = \frac{3}{x-2} - \sqrt{x-1}$
The domain of (f-g) ⇒⇒⇒ [1,∞) - {2}
because: x-2 = 0 ⇒⇒⇒ x = 2 and    x - 1 ≥ 0 ⇒⇒⇒ x ≥ 1

(5) $f * g = \frac{3}{x-2} * \sqrt{x-1} = \frac{3 \sqrt{x-1}}{(x-2)}$
The domain of (f*g) ⇒⇒⇒ [1,∞) - {2}
because: x-2 = 0 ⇒⇒⇒ x = 2 and    x - 1 ≥ 0 ⇒⇒⇒ x ≥ 1

(6) $f * f = \frac{3}{x-2} * \frac{3}{x-2} = \frac{9}{(x-2)^2}$
The domain of ff ⇒⇒⇒ R - {2}

Because ⇒⇒⇒ x-2 = 0 ⇒⇒⇒ x = 2

(7) $\frac{f}{g} = \frac{\frac{3}{x-2} }{ \sqrt{x-1} } = \frac{3}{(x-2) \sqrt{x-1}}$
The domain of (f/g) ⇒⇒⇒ (1,∞) - {2}
because: x-2 = 0 ⇒⇒⇒ x = 2 and    x - 1 > 0 ⇒⇒⇒ x > 1

(8) $\frac{g}{f} = \frac{ \sqrt{x-1} }{ \frac{3}{x-2} } = \frac{1}{3} (x-2) \sqrt{x-1}$
The domain of (g/f) ⇒⇒⇒ [1,∞) - {2}
Because: x - 2 = 0 ⇒⇒⇒ x = 2 and   x - 1 ≥ 0 ⇒⇒⇒ x ≥ 1
===================================================
(b)

(9) $(f + g)(x) = \frac{3}{x-2} + \sqrt{x-1}$

(10) $(f - g)(x) = \frac{3}{x-2} - \sqrt{x-1}$

(11) $(f * g)(x) = \frac{3}{x-2} * \sqrt{x-1} = \frac{3 \sqrt{x-1}}{(x-2)}$

(12) $(f * f)(x) = \frac{3}{x-2} * \frac{3}{x-2} = \frac{9}{(x-2)^2}$

(13) $\frac{f}{g} = \frac{\frac{3}{x-2} }{ \sqrt{x-1} } = \frac{3}{(x-2) \sqrt{x-1}}$

(14) $(\frac{g}{f})(x) = \frac{ \sqrt{x-1} }{ \frac{3}{x-2} } = \frac{1}{3} (x-2) \sqrt{x-1}$

7 0

3 years ago

A square patio has an area of 116 ft. how long is each side of the patio nearest 10th

Zielflug [23.3K]

Answer:

10.8 ft each side

sqrt of 116 = 10.77

3 0

3 years ago