Missing Part:
a. A red ball is drawn
b. A white ball is drawn
Answer:
a. 
b. 
Step-by-step explanation:
Given
First, we need to calculate the total
Solving (a): Probability of Red.
This is calculated by dividing number of red balls by the total
So:
Solving (a): Probability of White.
This is calculated by dividing number of white balls by the total
So:
-3x^2 - 10x + 5 = 0
Quadratic formula:
-b +/- sqrt[b^2 - 4(a)(c)]/2(a)
So. . . 10 +/- sqrt[(10^2) - 4(-3)(5)]/2(-3)
10 +/- sqrt[100+60]/ -6
10 +/- sqrt[160]/-6
replace the numbers given for x & y so
the equation becomes 3*(-3) + 2*(-4) =
3*-3 = -9
2*-4 = -8
-9 + -8 = -17
Answer:
Number of $5 bills = 32
Number of $10 bills = 14
Number of $20 bills = 8
Step-by-step explanation:
Let x number of $5, y number of $10 and z number of $20
The number of $5 bills exceeds twice the number of $10 bills by 4.
Therefore, x = 2y + 4
The number of $20 bills is 6 fewer than the number of $10 bills.
Therefore, z = y - 6
A wallet contains $460 in $5, $10, and $20 bills.
Therefore,
5x + 10y + 20z = 460
Substitute x and y into equation
5(2y+4) + 10y + 20(y-6) = 460
10y + 20 + 10y + 20y - 120 = 460
40y - 100 = 460
40y = 460 + 100
40y = 560
y = 14
- Put the value of y into x = 2y + 4 and solve for x
x = 2(14) + 4
x = 32
- Put the value of y into z = y - 6 and solve for z
z = 14 - 6
z = 8
Hence, the each type of bills,
Number of $5 bills = 32
Number of $10 bills = 14
Number of $20 bills = 8
Make f(x) = y
y = (15x + 50)/(x + 5)
Swap the x and y and make y the subject again
x = (15y + 50)/(y + 5)
x(y + 5) = 15y + 50
xy + 5x = 15y + 50
xy - 15y = 50 - 5x
y(x - 15) = 50 - 5x
y = (50 - 5x)/(x - 15)
So inverse function f^-1(x) = (50 - 5x)/(x - 15)
